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Artist 52 [7]
3 years ago
11

a 2kg marble is moving at 3 m/s when it strikes another 4kg marble moving in the opposite direction at -3 m/s. What will be the

velocity of the 4kg marble after the collision of the 2kg marble's new velocity is -4 m/s. Also state the direction of the 2kg marble after they hit.
Physics
1 answer:
Elan Coil [88]3 years ago
4 0
Momentum is conserved after the collision 

Momentum of 2 Kg before collision = 2 * 3 = 6
Momentum of 4 kg  before collision = 4 * -3 = -12

so 6 + -12 = 2 * -4 + 4 *x   where x is velocity of 4kg marble.

4x - 8 = -6
4x = 2
x = 0.5 

Velocity of 4 kg marble is 0.5 m/s after collision

The 2 kg marble will move in the opposite direction to which it was moving before the collision.
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Tju [1.3M]

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a. 4

Explanation:

Hi there!

The equation of kinetic energy (KE) is the following:

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v = speed of the car.

Let´s see how would be the equation if the velocity is doubled (2 · v)

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Distributing the exponent:

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3 years ago
3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.
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  • Frequency=v=4.75×10^12Hz
  • Wavelength=?

We know

\boxed{\sf \lambda=\dfrac{C}{V}}

\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}

\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m

\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m

4 0
2 years ago
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