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juin [17]
3 years ago
8

The reactants collect ____. ____ energy from the sun drives chemical reactions. The products include gluecose and ____, which is

released into the air
Chemistry
2 answers:
Masteriza [31]3 years ago
6 0

Answer: Sunlight, Light, Oxygen

Explanation:

The reactants collect Sunlight. Light energy from the sun drives chemical reaction. The products include Glucose and Oxygen which is released into the air.

This is photosynthesis, a process by which green plant produces their food in the presence of sunlight.

6CO2 + 6H2O + (Energy) ----> C6H12O6 + 6O2 .

Mrac [35]3 years ago
5 0

Answer:

The reactants collect __solar __. ____ energy from the sun drives chemical reactions. The products include gluecose and ___oxygen____, which is released into the air

Explanation:

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What are the missing coefficients for the chemical equation <br> [ ] Ca + [ ] O2 → [ ] CaO
katen-ka-za [31]

Answer:

{ \sf{[ 2] Ca_{(s)} + [1 ] O_{2(g)} → [ 2] CaO _{(s)}}}

4 0
2 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
jarptica [38.1K]
X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
x:=5.8* 16/84 
this is approximately 1.1
4 0
3 years ago
8. The following system contains 20.0 psi each of gases A and B in the end bulbs with an evacuated bulb in the centre. Both stop
Effectus [21]

Answer:

13.3

Explanation:

Before opening the stopcocks you have 40psi in total.

After that, those 40psi will be divided into 3bulbs, so 40/3=13.3psi for the system.

3 0
2 years ago
A 7.0 g sample of a hydrocarbon (a molecule that has only hydrogen and carbon) is subject to combustion analysis. The mass of CO
Akimi4 [234]

Answer: The empirical formula for the given compound is CH_2

Explanation:

The chemical equation for the combustion of compound having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=22.0g

We know that:

Molar mass of carbon dioxide = 44 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 22.0 g of carbon dioxide, \frac{12}{44}\times 22.0=6g of carbon will be contained.

For calculating the mass of hydrogen:

Mass of hydrogen = Mass of sample - Mass of carbon

Mass of hydrogen = 7.0 g - 6 g

Mass of hydrogen = 1.0 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{6g}{12g/mole}=0.5moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{1.0g}{1g/mole}=1.0moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.5 moles.

For Carbon = \frac{0.5}{0.5}=1

For Hydrogen  = \frac{1.0}{0.5}=2

Step 3: Taking the mole ratio as their subscripts.

The ratio of Fe : C : H = 1 : 2

Hence, the empirical formula for the given compound is C_{1}H_{2}=CH_2

4 0
3 years ago
Which of the following values are not equal to 1 mole?
Gekata [30.6K]

Answer:

none of them are equal to one mole

3 0
2 years ago
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