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juin [17]
3 years ago
8

The reactants collect ____. ____ energy from the sun drives chemical reactions. The products include gluecose and ____, which is

released into the air
Chemistry
2 answers:
Masteriza [31]3 years ago
6 0

Answer: Sunlight, Light, Oxygen

Explanation:

The reactants collect Sunlight. Light energy from the sun drives chemical reaction. The products include Glucose and Oxygen which is released into the air.

This is photosynthesis, a process by which green plant produces their food in the presence of sunlight.

6CO2 + 6H2O + (Energy) ----> C6H12O6 + 6O2 .

Mrac [35]3 years ago
5 0

Answer:

The reactants collect __solar __. ____ energy from the sun drives chemical reactions. The products include gluecose and ___oxygen____, which is released into the air

Explanation:

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Calculate the entropy change for the surroundings of the reaction below at 350K: N2(g) + 3H2(g) -&gt; 2NH3(g) Entropy data: NH3
krek1111 [17]

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction (\Delta S^o).

\Delta S^o=S_{product}-S_{reactant}

\Delta S^o=[n_{NH_3}\times \Delta S^0_{(NH_3)}]-[n_{N_2}\times \Delta S^0_{(N_2)}+n_{H_2}\times \Delta S^0_{(H_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0{(NH_3)} = standard entropy of NH_3

\Delta S^0{(H_2)} = standard entropy of H_2

\Delta S^0{(N_2)} = standard entropy of N_2

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (192.5J/K.mole)]-[1mole\times (191.5J/K.mole)+3mole\times (130.6J/K.mole)]

\Delta S^o=-198.3J/K

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

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Which three of the five items would be best to include in a safety contract?
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Answer:

Solution A is a Weak Alkali, Solution B is a strong Acid.

Explanation:

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