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rusak2 [61]
3 years ago
8

Two spherical objects are separated by a distance that is 9.00 X 10m The objects are initially electrically neutral and are very

small compared to the stance between them. Each objectures the same negative charge due to the addition of electrons. As a result, each experiences an lectr ic force that has a magnitude of 1.137 10 . How many electrons did t o produce the charge on one of the objects?
Physics
1 answer:
romanna [79]3 years ago
5 0

Answer: 3.2 * 10^-3 C

Explanation: In order to solve this problem we have to use the Coulomb force given by:

F=k*q^2/ d^2 where he consider the same charge for each point

so, we have

q^2= F*d^2/k= 1.137* (10 C*9*10m)^2/9*10^9 N*m^2/C^2)=3.2 * 10^-3 C.

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A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If
Salsk061 [2.6K]

Complete question:

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If the switch is closed at time t = 0 s, what is the current 7.0 ms later?

Answer:

The current in the circuit 7 ms later is 0.2499 A

Explanation:

Given;

Ideal inductor, L = 45-mH

Resistor, R =  60-Ω

Ideal voltage supply, V = 15-V

Initial current at t = 0 seconds:

I₀ = V/R

I₀  = 15/60 = 0.25 A

Time constant, is given as:

T = L/R

T = (45 x 10⁻³) / (60)

T = 7.5 x 10⁻⁴ s

Change in current with respect to time, is given as;

I(t) = I_o(1-e^{-\frac{t}{T}})

Current in the circuit after 7 ms later:

t = 7 ms = 7 x 10⁻³ s

I(t) = I_o(1-e^{-\frac{t}{T}})\\\\I =0.25(1-e^{-\frac{7*10^{-3}}{7.5*10^{-4}}})\\\\I = 0.25(0.9999)\\\\I = 0.2499 \ A

Therefore, the current in the circuit 7 ms later is 0.2499 A

6 0
3 years ago
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
masha68 [24]

<u>Answer:</u> The molar mass of metal (M) is 47.86 g/mol

<u>Explanation:</u>

Let the atomic mass of metal (M) be x

Atomic mass of (MO_2)=(x+32)g/mol

To calculate the mass of metal, we use the equation:

\text{Mass percent of metal}=\frac{\text{Mass of metal}}{\text{Mass of metal oxide}}\times 100

Mass percent of metal = 59.93 %

Mass of metal = x g/mol

Mass of metal oxide = (x + 32) g/mol

Putting values in above equation, we get:

59.93=\frac{x}{(x+32)}\times 100\\\\59.93(x+32)=100x\\\\x=47.86g/mol

Hence, the molar mass of metal (M) is 47.86 g/mol

6 0
3 years ago
Use the terms in the word box to label each class of lever and the diagram.
balu736 [363]
1st class lever the Fulcrum is between the load and the effort
2nd class lever the load is between the effort and the fulcrum
3rd class lever the effort is between the fulcrum and the load.
1)1st class lever
2)3rd class lever
3)2nd class lever
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3 0
3 years ago
A 2-inch, f/4 reflector has a focal length of:
Tema [17]
I’m pretty sure it’s 8 sorry if I’m wrong
5 0
3 years ago
002 10.0 points note: report your answer in joules here. a proton and an antiproton, both at rest with respect to one another, m
Ulleksa [173]
The mass of the proton is:
m_p = 1.67 \cdot 10^{-27} kg
and the mass of the antiproton is exactly the same, so the total mass of the two particles is 2m_p.

In the annihilation, all the mass of the two particles is converted into energy, and the amount of this energy is given by Einstein's equivalence between mass and energy:
E=Mc^2
where M is the mass converted into energy and c is the speed of light. In this example, M=2m_p, therefore the energy released is
E=2m_p c^2 = 2 (1.67 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2=3 \cdot 10^{-10}J
3 0
3 years ago
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