The acceleration of the ball is 1.27 X 10⁵ m/s²
The Newtons second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
Given,
Mass = 145 kg
Force = 18,400 N
We need to calculate the acceleration
Using formula of acceleration(a)
a = F/m where F= force and m= mass
Put the values in the formula,
a = 18,400/(145 X 10⁻³) = 1.27 X 10⁵ m/s²
Therefor, the acceleration of the ball is 1.27 X 10⁵ m/s².
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Answer:
Explanation:
Normal length of spring = 28.3 cm
stretched length of spring = 38.2 cm
length of extension = 38.2 - 28.3 = 9.9 cm
= 9.9 x 10⁻² m
force applied to stretch = .55 x 9.8 ( mg )
= 5.39 N
Force constant = force applied / extension
= 5.39 / 9.9 x 10⁻²
= .5444 x 10² N /m
= 54.44 N/m
Life stress is bad on the fold
Answer:
Volume flow rate = 
Explanation:
The volume flow rate through a channel can be gotten by multiplying its area and its velocity.
The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle
Cross-sectional area = 

volume flow rate= 
Volume flow rate = 
Answer:
lift force = 0.213 N
Drag force =
Explanation:
Given: velocity v = 10 m/s
w = 100 rev/sec
diameter d = 3cm
density D = 1.2kg/m3
lift force =
Substituting the values into the equation, we obtain
lift force = 0.213 N
Drag force = C*D*A*v/2
where C = 0.5
substituting the values into the equation again, we have
Drag force =