Answer:
a) 16 N
b) 2.13 m/s²
Explanation:
Draw a free body diagram of the tv stand. There are four forces:
Weight force mg pulling down,
Normal force N pushing up,
Friction force Nμ pushing left,
and applied force P pulling right.
Sum of forces in the y direction:
∑F = ma
N − mg = 0
N = mg
The net force in the x direction is:
∑F = P − Nμ
∑F = P − mgμ
∑F = 25 N − (7.5 kg) (10 m/s²) (0.12)
∑F = 16 N
Net force equals mass times acceleration:
∑F = ma
16 N = (7.5 kg) a
a = 2.13 m/s²
Refer to the diagram shown below.
Define
= unit vector in the eastern direction
= unit vector n the northern drection.
Then the displacement vectors are
Vector #1:
Vector #2:
Vector #3:
Because the vector sum of all three vector is zero, therefore
1381.1 +0.6561a - 0.891b = 0
703.7 - 0.9873a + 0.454b = 0
That is,
0.6561a - 0.891b = -1381.1 (1)
-0.9873a + 0.454b = -703.7 (2)
From (1), obtain
b = 0.7364a + 1550.1 (3)
Substitute (3) into (2).
-0.9873a + 0.454(0.7364a + 1550.1) = - 703.7
-0.653a = -1407.4
a = 2155.3 mles
From (3), obtain
b = 3137.2 mles
Answer:
The magnitudes of the two displacement vectors are
2155.3 miles and 3137.2 miles.
Answer:
8.27°
Explanation:
To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.
by a simple trigonometric relation you obtain that the angle:
hence, the angle between the rod and the horizontal is 8.27°
Answer:
y=-3.2x+18.5 Hope This Helps Tell me if you need step by step