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Korvikt [17]
3 years ago
6

20 cm long 10 cm wide and 5 cm thick as a mass of 500 g determine the greatest pressure that can be exerted by block on the flat

surface?​
Physics
1 answer:
uysha [10]3 years ago
8 0

100000 Pascal

Explanation:

pressure= force/area

Max pressure= force/min area

so f=5

min area= 5×10^-5

5÷5*10^-5 = 100000pascal

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A rectangular key was used in a pulley connected to a line shaft with a power of 7.46 kW at a speed of 1200 rpm. If the shearing
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Given:

Shaft Power, P = 7.46 kW = 7460 W

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width of key, w = \frac{d}{4}

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Solution:

Torque, T = \frac{P}{\omega }

where,

\omega = \frac{2\pi  N}{60}

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30\times 10^{6} = \frac{2\times 59.365}{\pi (\frac{d}{2})^{3}}

d = 0.0216 m

Now,

w =  \frac{d}{4} =  \frac{0.02116}{4} = 5.4 mm

Now, for shear stress in key

\tau _{key} = \frac{F}{wl}

we know that

T = F \times r =  F. \frac{d}{2}

⇒ \tau _{key} = \frac{\frac{T}{\frac{d}{2}}}{wl}

⇒ 240\times 10^{6} = \frac{\frac{59.365}{\frac{0.0216}{2}}}{0.054l}

length of the rectangular key, l = 4.078 mm

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