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Korvikt [17]
2 years ago
6

20 cm long 10 cm wide and 5 cm thick as a mass of 500 g determine the greatest pressure that can be exerted by block on the flat

surface?​
Physics
1 answer:
uysha [10]2 years ago
8 0

100000 Pascal

Explanation:

pressure= force/area

Max pressure= force/min area

so f=5

min area= 5×10^-5

5÷5*10^-5 = 100000pascal

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A halfback on an apparent breakaway for a touchdown is tackled from behind. If the halfback has a mass of 98 kg and was moving a
uranmaximum [27]

Answer:

The mutual speed immediately after the touchdown-saving tackle is 4.80 m/s

Explanation:

Given that,

Mass of halfback = 98 kg

Speed of halfback= 4.2 m/s

Mass of corner back = 85 kg

Speed of corner back = 5.5 m/s

We need to calculate their mutual speed immediately after the touchdown-saving tackle

Using conservation of momentum

m_{h}v_{h}+m_{c}v_{c}=m_{h+c}v_{h+c}

Where, m_{h}= mass of halfback

m_{c}=mass of corner back

v_{h}= velocity of halfback

v_{c}= velocity of corner back

Put the value into the formula

98\times4.2+85\times5.5=(98+85)\times v

v=\dfrac{98\times4.2+85\times5.5}{98+85}

v=4.80\ m/s

Hence, The mutual speed immediately after the touchdown-saving tackle is 4.80 m/s

3 0
3 years ago
One watt is A. equal to one kilogram per second B. the power that can be delivered by an average horse C. the same as one-foot p
Naddik [55]

Answer:

D. the proper replacement unit for one joule per second

Explanation:

When energy is divided by the time the energy was used we get power

P=\dfrac{E}{t}\\\Rightarrow P=\dfrac{mv^2}{t}\\\Rightarrow P=\dfrac{kg(\dfrac{m^2}{s^2})}{s}\\\Rightarrow P=kg(\dfrac{m^2}{s^2})}\times \dfrac{1}{s}\\\Rightarrow P=\dfrac{kgm^2}{s^3}

kg\dfrac{m^2}{s^2}=Joule

P=\dfrac{kgm^2}{s^3}

So, the answer is D. the proper replacement unit for one joule per second

8 0
3 years ago
What is a likely consequence of preventing prescribed burns to forest ecosystems?
liraira [26]

The forest ecosystem will regain back its natural ecology compared to burning of the forest and other illegal activities done to the forest. And also, some of the animals living in that forest will live and those that are endangered will not be threatened.

5 0
2 years ago
How many oxygen atoms are used to bond with sulfur in the compound "sulfur dioxide"?
kherson [118]
2 oxygen atoms are used to bond with sulfer
7 0
3 years ago
Read 2 more answers
For a certain optical medium the speed of light varies from a low value of 1.90 × 10 8 m/s for violet light to a high value of 2
Dmitry_Shevchenko [17]

Answer:

a. The refractive index ranges from 1.5 - 1.56

b. 18.7° for violet light and 19.5° for red light.

c. 33.7° for violet light and 35.3° for red light.

Explanation:

a. The refractive index of an object is the ratio of the speed of light in a vacuum and the speed of light in the object.

Mathematically,

n = \frac{c}{v}

The speed of violet light in the object is 1.9 * 10^8 m/s.

The speed of red light in the object is 2 * 10^8 m/s

Hence, the refractive index for violet light is:

n = \frac{3 * 10^8 }{1.9 * 10^8} \\\\n = 1.56

and for red light, it is:

n = \frac{3 * 10^8 }{2 * 10^8} \\\\n = 1.5

Hence, the refractive index ranges from 1.5 - 1.56.

b. The refractive index is also the ratio of the sine of the angle of incidence to the sine of the angle of refraction.

n = \frac{sin(i)}{sin(r)}

The angle of incidence is 30°.

The angle of refraction for violet light will be:

1.56 = \frac{sin(30)}{sin(r)}\\ \\sin(r) = \frac{sin(30)}{1.56}  = \frac{0.5}{1.56} \\\\sin(r) = 0.3205\\\\r = 18.7^o

And the angle of refraction for red light will be:

1.5 = \frac{sin(30)}{sin(r)}\\ \\sin(r) = \frac{sin(30)}{1.5}  = \frac{0.5}{1.5} \\\\sin(r) = 0.3333\\\\r = 19.5^o

The angle of refraction for red light is larger than that of violet light when the angle of incidence is 30°.

c. The angle of incidence is 60°.

The angle of refraction for violet light will be:

1.56 = \frac{sin(60)}{sin(r)}\\ \\sin(r) = \frac{sin(60)}{1.56}  = \frac{0.8660}{1.56} \\\\sin(r) = 0.5551\\\\r = 33.7^o

And the angle of refraction for red light will be:

1.5 = \frac{sin(60)}{sin(r)}\\ \\sin(r) = \frac{sin(60)}{1.5}  = \frac{0.8660}{1.5} \\\\sin(r) = 0.5773\\\\r = 35.3^o

The angle of refraction for red light is still larger than that of violet light when the angle of incidence is 60°.

6 0
3 years ago
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