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Vesnalui [34]
3 years ago
13

An 85.0-kg mountain climber plans to swing down, starting from rest, from a ledge using a light rope 6.50 m long. he holds one e

nd of the rope, and the other end is tied higher up on a rock face. since the ledge is not very far from the rock face, the rope makes a small angle with the vertical. at the lowest point of his swing, he plans to let go and drop a short distance to the ground.
Physics
1 answer:
Rainbow [258]3 years ago
4 0

Understanding the given:
85 kg mountain climber
6.50 m long rope
gravity = 10m/s2

If we want to identify the work done on this scenario 
we get f = 85kg x 10m/s2 = 850 N
w = 850N x 6.5 m = 5525 J

Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
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A car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has ___ energy
TiliK225 [7]

Answer:

KE = 1/2mv^2

KE = 1/2(1120)(40^2)

KE = 560(1600)

KE = 896000

Let me know if this helps!

4 0
3 years ago
A toy of mass 0.155 kg is undergoing simple harmonic motion (SHM) on the end of a horizontal spring with force constant 305 N/m
zzz [600]

Answer:

310.38\times 10^{-4}j

Explanation:

We have given mass m=0.155 kg

Force constant K = 305 N/m

Distance X=1.25\times 10^{-2}m

Velocity v=.305 m/sec

The total energy at any position of the motion is give by E=\frac{1}{2}mv^2+KX^2  here \frac{1}{2}mv^2 is energy due to motion and KX^2  is energy due to spring elongation

So total energy E=\frac{1}{2}\times 0.155\times 0.305^2+305\times 0.0125^2=310.38\times 10^{-4}j

4 0
3 years ago
Identify the type of chemical reaction that is described.
Anastasy [175]

Water breaks down into  hydrogen and oxygen: It is a decomposition reaction as a single substance decomposes to give two products.

H_2O \rightarrow H_2 +\frac {1}{2}O_2

Leaves make starch using  chlorophyll and carbon dioxide: Synthesis reaction: as the synthesis reaction involves two or more than two reactants which join together to result into a single main product along with the formation of simple by products.

6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2

Food burns in oxygen gas  and releases a lot of energy: Combustion: Combustion process involves the use of oxygen to give products along with release of energy.

C_6H_{12}O_6 + 6O_2\rightarrow 6CO_2 + 6H_2O

Adding vinegar (acid) to baking soda (alkali) gives  a product that is neither  acidic nor alkaline: Neutralization: acetic acid in vinegar reacts with soda (base) to give salt (neutral) and .

CH_3COOH + NaHCO_3\rightarrow CH_3COONa +H_2O + CO_2





6 0
4 years ago
Steve want to catch up to Cami, a girl he likes. If he is jogging at 8 m/s and she is walking at 1 m/s. How long will it take hi
Aleks04 [339]

Answer:

<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>

<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>

Explanation:

Distance between them is 10 m

Speed  ( if they are moving towards each other)= distance/time

time = 10/8+1

time = distance / speed= 10/9=  1.11 secs

if they are moving away from each other than it will take

time = 10/8-1= 10/7= 1.43 secs

5 0
3 years ago
A certain car's drive-train produces a force of 5300 N as it accelerates from 0
lakkis [162]

The power is 7.1\cdot 10^4 W

Explanation:

First of all, we need to find the acceleration of the car, which is given by

a=\frac{v-u}{t}

where

v = 60 mph = 26.8 m/s is the final velocity

u = 0 is the initial velocity

t = 10.0 s is the time

Substituting,

a=\frac{26.8-0}{10.0}=2.68 m/s^2

Now we can find the mass of the car by using Newton's second law:

F=ma

where

F = 5300 N is the force applied

m is the mass

a=2.68 m/s^2 is the acceleration

Solving for m,

m=\frac{F}{a}=\frac{5300}{2.68}=1978 kg

Now we can use the work-energy theorem, which states that the work done is equal to the change in kinetic energy of the car, to find the work:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2

And substituting,

W=\frac{1}{2}(1978)(26.8)^2-0=7.10\cdot 10^5 J

Finally, we can find the power output of the car:

P=\frac{W}{t}

where

W is the work

t = 10.0 s is the time elapsed

Substituting,

P=\frac{7.1\cdot 10^5}{10.0}=7.1\cdot 10^4 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

4 0
4 years ago
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