Answer:
Step-by-step explanation:
F(x) = 2^x
64 = 2^x
2^6 = 2^x
x = 6
f(x) = 2^x
log (f(x)) = x log 2
x = log (f(x)) / log 2 = log_2 (f(x))
Therefore, the required logarithmic function is x = log_2 (f(x))
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Lets do this:-
A. 7 Sandwiches
18 - 7 = 11
7 × $7.75 = $54.25
7 sandwiches cost $54.25.
11 × $4.50 = $49.50
11 soups costs $49.50
49.50 + 54.25 = 103.75
A is not d answer cuz d total of d lunches came to $113.50.
B. 8 sandwiches
18 - 8 = 10
8 × $7.75 = $62
8 sandwiches cost $62.
10 × $4.50 = 45
8 soups costs $45
62 + 45 = 107
B is not d answer cuz d total of d lunches came to $113.50.
C. 9 Sandwiches.
18 - 9 = 9
9 × $7.75 = 69.75
9 sandwiches cost $69.
9 × $4.50 = 40.50
9 soups costs $40.50
69 + 40.50 = 109.5
C is not d answer cuz d total of d lunches came to $113.50.
D. 10 Sandwiches
18 - 10 = 8
10 × $7.75 = $77.75
10 sandwiches cost $77.75.
8 × $4.50 = $36
8 soups costs $36.
77.75 + 36 = <span>113.75
</span>D is not d answer cuz d total of d lunches came to $113.50.
So, based on your answer choices there is no correct choice. <span />
Answer: Van = 198 students
bus = 672 students
Step-by-step explanation:
Let x represent the number of students in the vans and y represent the number of students in the buses, then from the first statement , we have
11x + 4y = 289 ................. equation 1
From the second statement, we also have
7x + 12y = 581 ............... equation 2
Combining the two equations together and solving simultaneously , we have
x = 11 and y = 42
therefore the number of students vans can carry will be'
11x + 7x
= 11(11) + 7 (11)
= 121 + 77
= 198
The number of students buses will carry will be
4y + 12y
= 4(42) + 12(42)
= 168 + 504
= 672
Answer:
The answer would have to be B
