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Alona [7]
2 years ago
14

How many grams of na2co3 would be needed to produce 1000g of nahco3

Chemistry
1 answer:
Ivenika [448]2 years ago
6 0

Answer:

630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃

Explanation:

The balanced reaction is:

Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 moles
  • CO₂: 1 mole
  • H₂O: 1 mole
  • NaHCO₃: 2 moles

Being the molar mass:

  • Na₂CO₃: 106 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole
  • NaHCO₃: 84 g/mole

Then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • CO₂: 1 mole* 44 g/mole= 44 g
  • H₂O: 1 mole* 18 g/mole= 18 g
  • NaHCO₃: 2 moles* 84 g/mole= 168 g

You can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?

mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}

mass of Na₂CO₃= 630.95 grams

<u><em>630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃</em></u>

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3 years ago
Which of the following is not true? a. The freezing point of sea water is lower than the freezing point of pure water. b. The bo
Anna007 [38]

Answer:

The false statement is b.

The boiling point of a water sample from the Salt Lake is lower than the boiling point of pure water

Explanation:

This excersise refers to colligative properties.

Boiling point refers to the property of boiling point elevation. In a solution of ions, as water sea or water from lakes, the boiling point will be higher than water pure.

It is logical to say that, because these sort of water have ions. Remember that colligative properties depends on the solute particles.

T° boiling solution - T° pure solvent = Kb . m . i

In the freezing point depression, we have the oppossite of boiling point elevation. Freezing point of solution is lower than pure solvent, according to this:

T° freezing pure solvent - T° freezing solution = Kc . m . i

We have to always consider the i, which means Van't Hoff factor, number of ions dissolved in solution. As the i is higher, the freezing point of solution will be lower, and the boiling point of solution will be higher.

They are true statement a and c.

In solution of., [NaCl] = 0.1M, as it is a higher concentration, the molality is also higher than a solution of [NaCl] = 0.05.

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5 0
3 years ago
PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!
Marina CMI [18]

Answer:

C

Explanation:

It afffects changes in pressure and temperature not melting and boiling points

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Answer:1 3 4 1 im pretty positive

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2 years ago
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What mass of AI2O3 forms from 16 g O2 and excess AI?
vlada-n [284]

Answer:

2Al+1.5O2→Al2O3

Thus, 2 mol of Al combine with 1.5 mol of oxygen to form 1 mol of Al2O3.

2 mol of Al corresponds to 2×27=54 g.

Thus, the weight of Al used in the reaction is 54 g.

4 0
2 years ago
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