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Alona [7]
3 years ago
14

How many grams of na2co3 would be needed to produce 1000g of nahco3

Chemistry
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃

Explanation:

The balanced reaction is:

Na₂CO₃ + CO₂+ H₂O → 2 NaHCO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 moles
  • CO₂: 1 mole
  • H₂O: 1 mole
  • NaHCO₃: 2 moles

Being the molar mass:

  • Na₂CO₃: 106 g/mole
  • CO₂: 44 g/mole
  • H₂O: 18 g/mole
  • NaHCO₃: 84 g/mole

Then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • CO₂: 1 mole* 44 g/mole= 44 g
  • H₂O: 1 mole* 18 g/mole= 18 g
  • NaHCO₃: 2 moles* 84 g/mole= 168 g

You can apply the following rule of three: if 106 grams of Na₂CO₃ are needed to produce 168 grams of NaHCO₃, how much mass of Na₂CO₃ is necessary to produce 1000 grams of NaHCO₃?

mass of Na_{2} CO_{3}=\frac{1000grams ofNaHCO_{3} *106gramsofNa_{2} CO_{3} }{168grams ofNaHCO_{3}}

mass of Na₂CO₃= 630.95 grams

<u><em>630.95 grams of Na₂CO₃ would be needed to produce 1000g of NaHCO₃</em></u>

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Answer:

(a)

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Explanation:

(a)

The given compound is silicon tetrabromide. It means that 1 silicon and four bromine atoms are combined to form the molecule.

The chemical formula of silicon tetrabromide is SiBr_4

(b)

The given compound is disulfur dichloride. It means that 2 sulfur atoms and 2 chlorine atoms are combined to form the molecule.

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(c)

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3 years ago
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Answer:

6. 7870 kg/m³ (3 s.f.)

7. 33.4 g (3 s.f.)

8. 12600 kg/m³ (3 s.f.)

Explanation:

6. The SI unit for density is kg/m³. Thus convert the mass to Kg and volume to m³ first.

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1m³= 1 ×10⁶ cm³

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= 64.2 ÷1000 kg

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= 8.16 cm³

= 8.16 ÷ 10⁶

= 8.16 \times 10^{ - 6} \:  kg

\boxed{density =  \frac{mass}{volume} }

Density of iron bar

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7.

\boxed{mass = density \:  \times volume}

Mass

= 1.16 ×28.8

= 33.408 g

= 33.4 g (3 s.f.)

8. Volume of brick

= 12 cm³

= 12  \times  10^{ - 6}  \: m^{3}  \\  = 1.2 \times 10^{ - 5}  \: m ^{3}

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