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Zina [86]
2 years ago
12

QUESTION THREE

Chemistry
1 answer:
BartSMP [9]2 years ago
8 0

Answer:

Odds to be given for an event that either Romance or Downhill wins is 11:4

Explanation:

Given an odd, r = a : b. The probability of the odd, r can be determined by;

     Pr(r) = \frac{a}{b} ÷ (

So that;

Odd that Romance will win = 2:3

Pr(R) = \frac{2}{3} ÷ (

        = \frac{2}{3} ÷ \frac{5}{3}

       = \frac{2}{5}

Odd that Downhill will win = 1:2

Pr(D) = \frac{1}{2} ÷ (

        =  \frac{1}{2} ÷ \frac{3}{2}

        = \frac{1}{3}

The probability that either Romance or Downhill will win is;

Pr(R) + Pr(D) = \frac{2}{5} +  \frac{1}{3}

                    = \frac{11}{15}

The probability that neither Romance nor Downhill will win is;

Pr(neither R nor D) = (1 - \frac{11}{15})

                               = \frac{4}{15}

The odds to be given for an event that either Romance or Downhill wins can be determined by;

                               = Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)

                               = \frac{11}{15} ÷ \frac{4}{15}

                              = \frac{11}{4}

Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4

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I'll answer the question by filling in the blank spaces

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