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3 years ago

What two processes practiced by scientists increase the likelihood of a successful outcome in science?

Physics

1 answer:

Amanda [17]3 years ago

5 0

Answer:

ULTIMATE CORRECT ANSWER

collaboration and communication

Explanation:

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If the electric field inside a capacitor exceeds the dielectric strength of the dielectric between its plates, the dielectric wi

ahrayia [7]

Answer:

The max. Energy that can be stored in the neoprene rubber capacitor will be 0.304J

Explanation:

Detailed explanation and calculation is shown in the image below

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3 years ago

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Do these for me please

Svetach [21]

Answer:

do what for you there is no question???

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3 years ago

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A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. After a short rest at the lake, she hi

7nadin3 [17]

1) Magnitude

Let's take south as positive y-direction and east as positive x-direction. Then we have to resolve both displacements into their respective components:

$d_{1x} = -(3.5 km) cos 55^{\circ}=-2.0 km$

$d_{1y} = (3.5 km) sin 55^{\circ}=2.87 km$

$d_{2x} = (2.7 km) sin 16^{\circ}=0.74 km$

$d_{2y} = (2.7 km) cos 16^{\circ}=2.60 km$

So, the components of the total displacement are

$d_x = d_{1x}+d_{2x}=-2.0 km +0.74 km=-1.26 km$ east (so, 1.26 km west)

$d_y=d_{1y}+d_{2y}=2.87 km + 2.60 km=5.47 km$ south

So, the magnitude of the resultant displacement is

$d=\sqrt{d_x^2+d_y^2}=\sqrt{(1.26)^2+(5.47)^2}=5.61 km$

2) Direction

the direction of the hiker's displacement is

$\theta= arctan(\frac{d_y}{d_x})=arctan(\frac{5.47}{1.26})=arctan(4.34)=77.0^{\circ}$ south of west.

3 0

4 years ago

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A 0.537-kg basketball is dropped out of a window that is 5.88 m above the ground. The ball is caught by a person whose hands are

jeka57 [31]

Answer:

a) 20.54 J

b) 30.97 J

c) 10.43 J

d) -20.54 J

Explanation:

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

h = Height

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88-1.98)\\\Rightarrow W=20.54\ J$

Work done by the ball's weight is 20.54 J

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (5.88)\\\Rightarrow W=30.97\ J$

Gravitational potential energy of the basketball, relative to the ground, when it is released is 30.97 J

$W=mgh\\\Rightarrow W=0.537\times 9.81\times (1.98)\\\Rightarrow W=10.43\ J$

Gravitational potential energy of the basketball, relative to the ground, when it is released is 10.43 J

Change in gravitational potential energy

$\Delta U=10.43-30.97=-20.54\ J$

Change in gravitational potential energy is given by -20.54 J

5 0

4 years ago

Question 1 of 15

Ierofanga [76]

Answer:

d 75 miles per hour

Explanation:

60 ÷ 20

3 × 25 = 75

hoped that helped!!

8 0

3 years ago