Question 1 of 15

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated by a distance d is

romanna [79]

Answer:

The net force exerted by the two charges is 10.97 x 10⁻⁵ N along negative x-direction.

Explanation:

K=1/4πϵ0, where ϵ0=8.854×10−12C2

K = 9x10⁹

The electric force on point charge q₃ due to charge q₂ is

F₃₂ = kq₃q₂ / (1.245)²

= (9x10⁹ * 49.5x10⁻⁹ * 30.5x10⁻⁹) / (1.245)²

= 13,587.75 x 10⁻⁹ / 1.55

= 8.76629 x 10⁻⁵ N

The electric force on point charge q₃ due to charge q₁ is

F₃₁ = kq₃q₁ / (1.695 - 1.245)²

= (9x10⁹ * 49.5x10⁻⁹ * 10.0x10⁻⁹) / 0.2025

= 2.2000 x 10⁻⁵ N

The net electric force on point charge q₃ is

F₃ = -F₃₁ - F₃₂

= - 8.76629 x 10⁻⁵ N - 2.2000 x 10⁻⁵ N

= 10.97 x 10⁻⁵ N along negative x-direction

7 0

4 years ago

A confined aquifer with a porosity of 0.15 is 30 m thick. The potentiometric surface elevation at two observation wells 1000 m a

AlekseyPX

Answer:

Part (a) The flow rate per unit width of the aquifer is 1.0875 m³/day

Part (b) The specific discharge of the flow is 0.0363 m/day

Part (c) The average linear velocity of the flow is 0.242 m/day

Part (d) The time taken for a tracer to travel the distance between the observation wells is 4132.23 days = 99173.52 hours

Explanation:

Part (a) the flow rate per unit width of the aquifer

From Darcy's law;

$q = -Kb\frac{dh}{dl}$

where;

q is the flow rate

K is the permeability or conductivity of the aquifer = 25 m/day

b is the aquifer thickness

dh is the change in th vertical hight = 50.9m - 52.35m = -1.45 m

dl is the change in the horizontal hight = 1000 m

q = -(25*30)*(-1.45/1000)

q = 1.0875 m³/day

Part (b) the specific discharge of the flow

$V = \frac{Q}{A} = \frac{q}{b} = -K\frac{dh}{dl}\\\\V = -(25 m/d).(\frac{-1.45 m}{1000 m}) = 0.0363 m/day$

V = 0.0363 m/day

Part (c) the average linear velocity of the flow assuming steady unidirectional flow

Va = V/Φ

Φ is the porosity = 0.15

Va = 0.0363 / 0.15

Va = 0.242 m/day

Part (d) the time taken for a tracer to travel the distance between the observation wells

The distance between the two wells = 1000 m

average linear velocity = 0.242 m/day

Time = distance / speed

Time = (1000 m) / (0.242 m/day)

Time = 4132.23 days

$= 4132.23 days *\frac{24 .hrs}{1.day} = 99173.52, hours$

4 0

3 years ago

PLEASE HELPPPPP!!!!! ILL GIVE CROWN

snow_lady [41]

Answer:To understand the regional and local climates of Colorado, you must begin with a basic knowledge of Colorado's topography. Colorado lies astride the highest mountains of the Continental Divide. Nearly rectangular, its north and south boundaries are the 41° and 37° N. parallels, and the east and went boundaries are the 102° and 109° W. meridians. It is eighth in size among the 50 states, with an area of over 104,000 square miles. Although known for its mountains, nearly 40 percent of its area is taken up by the eastern high plains.

Of particular importance to the climate are Colorado's interior continental location in the middle latitudes, the high elevation of the entire region, and the mountains and ranges extending north and south approximately through the middle of the State. With an average altitude of about 6,800 feet above sea level, Colorado is the highest contiguous State in the Union. Roughly three-quarters of the Nation's land above 10,000 feet altitude lies within its borders. The State has 59 mountains 14,000 feet or higher, and about 830 mountains between 11,000 and 14,000 feet in elevation.

Explanation:

4 0

3 years ago

Read 2 more answers

G Railroad tracks are made from segments L = 79 m long at T = 20° C. When the tracks are laid, the engineers leave gaps of width

Andreyy89

Answer:

$l=L\alpha(T_c-T)$

Explanation:

L = Initial length of segment = 79 m

T = Normal temperature = $20^{\circ}\text{C}$

l = Width to be left for expansion

$\alpha$ = Coefficient of linear expansion of the material = $12\times 10^{-6}^{\circ}\text{C}^{-1}$

$T_c$ = Maximum temperature = $39.5^{\circ}\text{C}$

$\Delta T$ = Change in temperature = $T_c-T$

The expression of linear expansion is given by

$l=L\alpha\DeltaT\\\Rightarrow l=L\alpha(T_c-T)$

The expression for the minimum gap distance l the engineers must leave for a track rated at temperature $T_c$ is $l=L\alpha(T_c-T)$

8 0

3 years ago

Why do scientists need a standard system of measurement?

ladessa [460]

Scientists need a standard system of measurement to allow for consistency with measurement data (A). Scientists would not be able to understand what other scientists are saying if everyone uses their own system of measurement. Scientists need to take measurements, interpret them and communicate the results to other scientists. That is why a standardized system of taking measurements has been developed. The International System of Units or the Metric system is the measurement system of choice for scientists all over the world today.

6 0

3 years ago