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3 years ago

If you can help answer the question if you can't then don't

Chemistry

1 answer:

vampirchik [111]3 years ago

4 0

Answer:

Yes its both a physical and chemical change heres why.

When heated , the wax melts to form a liquid wax . The liquid wax then becomes a solid wax upon cooling ( Physical change )

When the candle is lit, the wax near the tip of the candle will melt . The wick then absorbs the liquid wax . The liquid wax then vapourizes due to the heat emitting from the flame . The wax vapour then burns to give off a black substance ( what we will to as CO₂ , soot ) , heat and water vapour

(Chemical change )

Brainliest ? Hope I answered your question

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Calculate the energy of a photon of this light wave in joules. [Show all calculations, including the equation and substitution w

Ket [755]

The energy of the photon from the calculation performed is 3.5 * 10^-16 J.

<h3>What is a photon?</h3>

A photon is a packet of light. It was derived from the theory of Albert Einstein. The energy of a photon is obtained from; E = hc/λ

h= Plank's constant
c = speed of light
λ = wavelength

Now we have that;

E = 6.6 * 10^-34 * 3 * 10^8/562 * 10^-9

E = 3.5 * 10^-16 J

Missing parts:

Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm?

Learn more about energy of photon:brainly.com/question/20912241

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7 0

2 years ago

Oxidation number is

zavuch27 [327]

The correct letter to your answer would be A

5 0

3 years ago

An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0

Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

Volume of the gas in the tank (V₁): 200.0 L

Pressure of ethylene gas in the tank (P₁): ?

Volume of the gas in the torch (V₂): 300 L

Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

$P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm$

3 0

3 years ago

(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of

Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

$P x V = k$

Therefore, for this problem the step by step explanation is:

$P_{1} xV_{1} = P_{2} xV_{2}$

Clearing P2 and replacing

$P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm$

7 0

3 years ago

Write E in the blank if the material is heterogeneous or O if it is homogeneous.

Advocard [28]

Answer/Explanation:

Wood: E

Freshly brewed black coffee: O

Water: O

Lucky Charms: E

Salt: O

Dirt: E

Sausage and mushroom pizza: E

Air: O

Milk: O

Gold: O

Any mixture that looks the same through the substance is homogenous. The different parts are unable to be visibly seen. (Any periodic element is homogenous)

Any mixture that can be easily determined a mix and cannot be evenly separated or dispersed is heterogenous.

8 0

2 years ago