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Pie
3 years ago
11

What is the mole fraction of water in pure water

Chemistry
1 answer:
irinina [24]3 years ago
5 0
In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
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What would be the change in pressure in a sealed 10.0 l vessel due to the formation of n2 gas when the ammonium nitrite in 2.40
larisa86 [58]

The  change  in pressure in a sealed 10.0L vessel  is 5.28 atm

<u><em>calculation</em></u>

The pressure is calculated using the ideal gas equation

That is   P=n RT

where;

P (pressure)= ?

v( volume) = 10.0 L

n( number of moles)  which is calculated as below

<em>write the equation  for  decomposition  of   NH₄NO₂</em>

NH₄NO₂  →  N₂  +2H₂O

<em>Find the moles of NH₄NO₂</em>

 moles = molarity x volume in liters

= 2.40 l x 0.900 M =2.16 moles

<em>Use the mole ratio to determine the  moles of N₂</em>

that is from equation above  NH₄NO₂:N₂ is 1:1 therefore the moles of N₂ is also =2.16 moles

R(gas constant) =0.0821 l.atm/mol.K

T(temperature)  = 25° c  into kelvin = 25 +273 =298 K

make p the  subject of the formula  by diving both side  by  V

P = nRT/V

p ={ (2.16 moles x 0.0821 L.atm/mol.K  x 298 K) /10.0 L} = 5.28  atm.




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What are the main method of combination?<br><br>​
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7 0
3 years ago
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Tems11 [23]

Answer:

Following are the explanation to this question:

Explanation:

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Following are the description of the given reaction:

In reaction A:

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In reaction B:

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