What kind of air is found in each high and low pressure area

Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s

Molodets [167]

Answer:

HOFO = (0, 0, +1, -1)

Explanation:

The formal charge (FC) can be calculated using the following equation:

$FC = V - N - \frac{1}{2}B$

<u>Where:</u>

V: are the valence electrons

N: are the nonbonding electrons

B: are the bonding electrons

The arrange of the atoms in the oxyacid is:

H - O₁ - F - O₂

Hence, the formal charge (FC) on each of the atoms is:

H: FC = 1 - 0 - 1/2*(2) = 0

O₁: FC = 6 - 4 - 1/2*(4) = 0

F: FC = 7 - 4 - 1/2*(4) = +1

O₂: FC = 6 - 6 - 1/2*(2) = -1

We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.

I hope it helps you!

3 0

3 years ago

An acid with molar mass 84.48 g/mol is titrated with 0.650 M KOH. What volume of KOH solution is needed to titrate 1.70 grams of

RSB [31]

Answer:

$V=0.0310L=3.10mL$

Explanation:

Hello.

In this case, since the acid is monoprotic and the KOH has one hydroxyl ion only, we can see that at the equivalence point the moles of both of them are the same:

$n_{acid}=n_{KOH}$

Thus, since we are given 1.70 g of the acid, we compute the moles of acid that were titrated:

$n_{acid}=1.70g*\frac{1mol}{84.48g}=0.0201mol$

Which equal the moles of KOH. In such a way, since the molarity is defined as moles over liters (M=n/V), the liters are moles over molarity (V=n/M), thus, the resulting volume is:

$V=\frac{0.0201mol}{0.650mol/L}\\\\V=0.0310L=3.10mL$

Best regards!

7 0

3 years ago

What is the part of the cartridge that actually flies outward (the projectile)?

zhannawk [14.2K]

Answer:

the culotte, the fulminant capsule and the sheath or cap together with remains of powder

Explanation:

A bullet has a nose, sheath or casing, a short propellant charge, and a capsule.

All these components are part of the vouchers. The classification of these is in metallic and semi-metallic.

3 0

2 years ago

Part d based on your answer to part c, how many bonding electrons and lone pair electrons (nonbonding electrons) are there in th

elena55 [62]

The Lewis Structure of HCN is shown below,

Number of Bonding Electrons:
In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,

Number of Bonding Electrons = 8

Number of Non-Bonding Electrons:
In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence,
Number of Non-Bonding Electrons = 2

Result:

Number of Bonding Electrons = 8

Number of Non-Bonding Electrons = 2

3 0

3 years ago

Which probably best indicates that a compound contains an ionic bond

alex41 [277]

I’m thinking

It conducts electricity when Molten.

5 0

3 years ago