I know that this was 6 days ago but you might have to include a picture or write a full sentence in order to get answers.
Answer:
The volume is 50, 74 l
Explanation:
We use the formula PV = nRT. The temperature in Kelvin is = 273+ 20 =293K
PV=nRT ---> V = (nRT) / P
V= (2.0 mol x 0,082 l atm /K mol x 293 K) / 0,947 atm
V=50,74128828 l
Answer:
ΔG°′ = 1.737 KJ/mol
Explanation:
The reaction involves the transfer of two electrons in the form of hydride ions from reduced coenzyme Q, CoQH₂ to fumarae to form succinate and oxidized coenzyme Q, CoQ.
The overall equation of reaction is as follows:
fumarate²⁻ + CoQH₂ ↽⇀ succinate²⁻ + CoQ ; ΔE∘′=−0.009 V
Using the equation for standard free energy change; ΔG°′ = −nFΔE°′
where n = 2; F = 96.5 KJ.V⁻¹.mol⁻¹; ΔE°′ = 0.009 V
ΔG°′ = - 2 * 96.5 KJ.V⁻¹.mol⁻¹ * 0.009 V
ΔG°′ = 1.737 KJ/mol
Answer:
<h2>9.46 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 1892.6 g
volume = 200 mL
We have
We have the final answer as
<h3>9.46 g/mL</h3>
Hope this helps you
You can <span>ensure that all the spectroscopes created the same calibration line and equation by calibrating the equipment. It is a very important step in the use of this equipment. In order to say they are the same, you need to obtain an equation of a line that relates absorbance or transmittance and concentration. Hope this helps.</span>
