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3 years ago

Describe how a crystal of alum differs from a crystal of potassium aluminum sulfate

1 answer:

7 0

An alum is a double salt where you have a trivalent metal sulfate and a monovalent metal sulfate. Meanwhile, a crystal of potassium aluminum sulfate is potash alum!

You might be interested in

What volume is occupied by 100.0 grams of chlorine gas (Cl2) at STP

Hatshy [7]

Moles of chlorine gas = 100/70.906 = 1.41 moles.

Therefore volume of Cl2 at STP = moles of Cl2 x 22.4 = 1.41 x 22.4 = 31.584 liters.

Hope this helps!

7 0

3 years ago

The ph of a buffered solution (select all that apply):

Svetllana [295]

What are the answer choices?

6 0

3 years ago

The titration of a 20.0-mL sample of an H2SO4 solution of unknown concentration requires 22.60 mL of a 0.158 M KOH solution to r

soldier1979 [14.2K]

Answer:

M₁ = 0.178 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid,

M₂ = concentration of base ,

V₂ = volume of base,

from , the question ,

M₁ = ?

V₁ = 20.0 mL

M₂ = 0.158 M

V₂ = 22.60 mL

Using the above formula , the molarity of the acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 20.0 mL = 0.158 M * 22.60 mL

M₁ = 0.178 M

5 0

4 years ago

The element chlorine has two stable isotopes, chlorine-35 with a mass of 34.97 amu and chlorine-37 with a mass of 36.95 amu. Fro

sergejj [24]

<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

<u>Explanation:</u>

We are given the two stable isotopes of chlorine with their respective masses. The average atomic mass of chlorine is also given.

Average atomic mass of chlorine = 35.45 amu.

Let us assume the fractional abundance of one isotope be 'x' and the fractional abundance for another isotope will be (1 - x) because the total fractional abundance is always equal to 1.

For Chlorine-35 isotope:

Fractional abundance = x

Mass = 34.97 amu

For Chlorine-37 isotope:

Fractional abundance = 1 - x

Mass = 36.95 amu

The formula for the calculation of average atomic mass is given by:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Putting values in above equation, we get:

$35.45=34.97(x)+36.95(1-x)\\\\35.45=34.97x+36.95-36.95\\\\-1.5=-1.98x\\\\x=\frac{-1.5}{-1.98}=0.7575$

$1-x=1-0.7575=0.2424$

Converting these two fractional abundances into percentage abundances by multiplying it with 100.

$x=0.7575\times 100=75.75\%\\\\1-x=0.2424\times 100=24.24\%$

Hence, one isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

7 0

3 years ago

What is the correct way to write 1,550,000,000 in scientific notation?

mr_godi [17]

Answer: a

Explanation:

scientific notation is about how many places passed the decimial place you are moving. therefor in order to get 1,550,000,000 you would move the decimial from 1.55 over nine times to the right

4 0

4 years ago

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