All categories

3 years ago

Which tool would you use to measure the height of a cube of metal

2 answers:

3 0

It depends on the size of the cube, but you could use a ruler for almost any size, or if it is small enough, you could use a caliper to get a very precise measurement.

victus00 [196]3 years ago

3 0

It really depends on the size.. if its huge i would use a meter ruler, if it is small use a reguler ruler...

You might be interested in

Three masses (3 kg, 5 kg, and 7 kg) are located in the xy-plane at the origin, (2.3 m, 0), and (0, 1.5 m), respectively.

Artist 52 [7]

Answer:

a) C.M $=(\bar x, \bar y)=(0.767,0.7)m$

b) $(x_4,y_4)=(-1.917,-1.75)m$

Explanation:

The center of mass "represent the unique point in an object or system which can be used to describe the system's response to external forces and torques"

The center of mass on a two dimensional plane is defined with the following formulas:

$\bar x =\frac{\sum_{i=1}^N m_i x_i}{M}$

$\bar y =\frac{\sum_{i=1}^N m_i y_i}{M}$

Where M represent the sum of all the masses on the system.

And the center of mass C.M $=(\bar x, \bar y)$

Part a

$m_1= 3 kg, m_2=5kg,m_3=7kg$ represent the masses.

$(x_1,y_1)=(0,0),(x_2,y_2)=(2.3,0),(x_3,y_3)=(0,1.5)$ represent the coordinates for the masses with the units on meters.

So we have everything in order to find the center of mass, if we begin with the x coordinate we have:

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)}{3kg+5kg+7kg}=0.767m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)}{3kg+5kg+7kg}=0.7m$

C.M $=(\bar x, \bar y)=(0.767,0.7)m$

Part b

For this case we have an additional mass $m_4=6kg$ and we know that the resulting new center of mass it at the origin C.M $=(\bar x, \bar y)=(0,0)m$ and we want to find the location for this new particle. Let the coordinates for this new particle given by (a,b)

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)}{3kg+5kg+7kg+6kg}=0m$

If we solve for a we got:

$(3kg*0m)+(5kg*2.3m)+(7kg*0m)+(6kg*a)=0$

$a=-\frac{(5kg*2.3m)}{6kg}=-1.917m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)}{3kg+5kg+7kg+6kg}=0m$

$(3kg*0m)+(5kg*0m)+(7kg*1.5m)+(6kg*b)=0$

And solving for b we got:

$b=-\frac{(7kg*1.5m)}{6kg}=-1.75m$

So the coordinates for this new particle are:

$(x_4,y_4)=(-1.917,-1.75)m$

5 0

3 years ago

Motion *

fomenos

Answer:

occurs when object changes position

Explanation:

when an object changes position with respect to others it is called motion

3 0

3 years ago

During which phase of the moon can a lunar eclipse happen?.

Umnica [9.8K]

Full moon!

when Earth is exactly between the Moon and Sun, Earth's shadow falls upon the surface of the Moon, dimming it and sometimes turning the surface red over the course of a few hours.

7 0

2 years ago

What is an internal resistance?

denpristay [2]

Answer:

Internal resistance refers to the opposition to the flow of current offered by the cells and batteries themselves resulting in the generation of heat. Internal resistance is measured in Ohms. ... Example: 1 The potential difference across the cell when no current flows through the circuit is 3 V.

Thank you hope it is helpful to you if it is helpful then plz mark me as the brainlist

8 0

3 years ago

You are driving a metric car that has a speedometer that displays in meters per second. When you look down at your speedometer,

Otrada [13]

Answer:

0.33m/s²

Explanation:

Given parameters:

Initial velocity = 19.9m/s

Final velocity = 4.4m/s

Time = 47.6s

Unknown:

Acceleration = ?

Solution:

To solve this problem, we use the expression below:

Acceleration = $\frac{v - u }{t}$

v is the final velocity

u is the initial velocity

t is the time taken

Acceleration = $\frac{4.4 - 19.9}{47.6}$

Acceleration = -0.33m/s²

This is a deceleration

6 0

3 years ago