I think the answer is B but not too sure.
The answer is d. I hope that helps.
<span>This problem asks that we compute the magnitude
of the maximum stress that exists at the tip of an internal crack
</span> sigmam=2*(sigma0)(a/(pt))^(1/2)
sigmam= 2*(180)*(((3.5×10^-2)/(2))/(4.5×10-4))^(1/2)=2245 MPA (325609.7 PSI)
The answer is c you got to look for answers that make sense
Answer:
5.6875 × 10^(10) electrons
Explanation:
To some this we will use the formula;
q = ne
Where;
q is charge
n is number of electrons
e is electron charge = 1.6 × 10^(-19) C
We are given q = -9.10 nc
1 nc = 10^(-9) C
Thus;
q = -9.1 × 10^(-9) C
Since q is negative, then e = -1.6 × 10^(-19) C
Thus;
-9.1 × 10^(-9) = n(-1.6 × 10^(-19))
n = -(9.1 × 10^(-9))/(-1.6 × 10^(-19))
n = 56875000000 electrons = 5.6875 × 10^(10) electrons