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insens350 [35]
3 years ago
12

You are driving a metric car that has a speedometer that displays in meters per second. When you look down at your speedometer,

you see that it reads 19.9 m/s, then 47.6 s later you look down and it reads 4.4 m/s. What is your average acceleration over those 47.6 s?
Physics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

0.33m/s²

Explanation:

Given parameters:

Initial velocity  = 19.9m/s

Final velocity  = 4.4m/s

Time  = 47.6s

Unknown:

Acceleration  = ?

Solution:

To solve this problem, we use the expression below:

     Acceleration  = \frac{v - u }{t}

v is the final velocity

u is the initial velocity

 t is the time taken

    Acceleration  = \frac{4.4  - 19.9}{47.6}  

    Acceleration = -0.33m/s²

This is a deceleration

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How do speed and acceleration differ
Savatey [412]

Speed is how fast you cover a distance.

           (distance covered) divided by (time to cover the distance).

Acceleration is any change in your motion ... speeding up,
slowing down, or changing the direction you're headed.

4 0
3 years ago
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A snowboarder starts from rest at the top of a slope. They accelerate to 35 m/s over 9 seconds. What is their acceleration?
leonid [27]
  • a=v-u/t

v=35m/s

t=9

  • a=35/9
  • a=3.88m/s²
4 0
3 years ago
Which of the following is maintained across the terminals of a battery? A. a potential difference B. a voltage drop C. an electr
serious [3.7K]
I believe the answer is C. An electric charge
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3 years ago
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If the ultraviolet photon has a wavelength of 249 nm and one of the photons emitted by the fluorescent material has a wavelength
melamori03 [73]

Answer:

601 nm

Explanation:

Energy of photon having wavelength of λ nm

= \frac{1244}{\lambda}eV

Energy of 249 nm photon

=\frac{1244}{249}

=4.996 eV

Similarly energy of 425nm photon

=\frac{1244}{425}

=2.927 eV

Difference = 2.069 eV.

This energy will give rise to another photon whose wavelength will be

λ = \frac{1244}{2.069}

= 601 nm.

6 0
4 years ago
The two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent (radiation can get in) are visible l
Svet_ta [14]

The two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.

<h3>What is electromagnetic spectrum?</h3>

The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.

They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.

Thus, the two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.

Learn more about electromagnetic spectrum.

brainly.com/question/23727978

#SPJ1

7 0
3 years ago
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