Question

A golf ball thrown at an angle of 20 relative to the ground at a speed of 40 m/s. if the range of the motion is 55m. what is the maximum height that the ball reaches

Answer 1

Answer:

Maximum height reached is given as H = 5.00 m

Explanation:

As we know that if the ball is projected at some angle with the horizontal then the range of the projectile is given by the formula

$R = \frac{v^2 sin2\theta}{g}$

here we have

$R = 55 m$

$\theta = 20^o$

v = 40 m/s

Now we have

$55 = \frac{40^2 sin40}{g}$

$g = 18.7 m/s^2$

now for maximum height we have

$H = \frac{v^2sin^2\theta}{2g}$

$H = \frac{40^2 sin^220}{2(18.7)}$

$H = 5 m$