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erica [24]
3 years ago
15

Find an equation for the plane that passes through the point [1, 1, 8] and that has [-1, -6, 3] as normal vector.

Physics
1 answer:
OlgaM077 [116]3 years ago
3 0
The normal to the plane is (Fx, Fy, Fz) = (1, 1, 8)
We have (x0, y0, z0) = (-1, - 6, 3)

Equation of the plane:
Fx(x - x0) + Fy(y - y0) + Fz(z - z0) = 0
=> (1)(x + 1) + (1)(y + 6) + (8)(z - 3) = 0
=> x + 1 + y + 6 + 8z - 24 = 0
=> x + y + 8z = 17
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Hi there!

According to Newton's second law:

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Answer:

0.45 seconds

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<em>t = -4.5 / -10</em>

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