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schepotkina [342]
3 years ago
11

The volume of a gas is 17.5 mL at 29◦C and

Chemistry
1 answer:
mars1129 [50]3 years ago
8 0

Answer: V = 14.4 mL

Explanation:

In this case, we'll use the ideal gas formula:

PV = nRT

Where:

P: pressure in atm

V: volume in liter

n: moles

R: gas constant (In this case 0.082 L atm/mol K)

T: temperature in K

We have data for the gas at first, so we can actually calculate the moles used, which will be constant even at different temperature and pressure. Let's calculate the moles:

n = PV/RT

Before we do this, let's convert the volume and temperature:

T = 29 + 273 = 302 K

V = 17.5 / 1000 = 0.0175 L

Now the moles:

n = 0.863 * 0.0175 / 0.082 * 302 = 0.00061 moles

with these moles, let's convert the temperature to K:

T2 = 13 + 273 = 286 K

and to calculate the volume:

V = nRT/P

so:

V = 0.00061 * 0.082 * 286 / 0.994

V = 0.0144 L or simply 14.4 mL

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BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

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<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

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B. The number of SO_2 molecules in 9.87 moles of SO_2:

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C. The moles of Fe in 1.40 x 10^{22} atoms of Fe:

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0.2324754694 x 10^{-1} moles.

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2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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