Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Answer:
(C) 220
Step-by-step explanation:
Let x represent the number of adult tickets sold and y represent the number of student tickets sold. With the information given, we can set up two equations:
(Since for every adult ticket sold, $5 is made and for every student ticket sold, $3 is made)
In the first equation, we can represent x in terms of y:

And then, we can substitute x in the second equation for 360 - y to get:
which simplifies to:
and therefore,
.
Hope this helps :)
Answer:
its the 3rd one
Step-by-step explanation:
Answer:
look above
Step-by-step explanation:
hope it hepls