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3 years ago

What is the maximum number of electrons that can occupy an orbital labeled dxy?

Chemistry

1 answer:

Rina8888 [55]3 years ago

6 0

2 is the maximum number of electrons that can occupy an orbital labeled dyx
Hope this help :)

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CAN SOMEONE PLEASE HELP ME I DON’T UNDERSTAND :(

masya89 [10]

Answer:

A supersaturated solution

6 0

3 years ago

Consider the reaction: N2(g) + O2(g) ⇄ 2NO(g) Kc = 0.10 at 2000oC Starting with initial concentrations of 0.040 mol/L of N2 and

IrinaVladis [17]

Answer:

0.011 mol/L

Explanation:

This can be solved with something called an ICE table.

I = initial

C = change

E = equilibrium

Initially, there is 0.04 M of N₂, 0.04 M of O₂, and 0 M of NO.

x amount of N₂ reacts. Since the stoichiometry is 1:1, x amount of O₂ also reacts. This produces 2x of NO.

After the reaction, there is 0.04-x of N₂, 0.04-x of O₂, and 2x of NO.

Here it is in table form:

$\left[\begin{array}{cccc}&N2&O2&NO\\I&0.04&0.04&0\\C&-x&-x&+2x\\E&0.04-x&0.04-x&2x\end{array}\right]$

Now we can use the equilibrium constant:

Kc = [NO]² / ( [N₂] [O₂] )

Substituting:

0.10 = (2x)² / ( (0.04 - x) (0.04 - x) )

Solving:

0.10 = (2x)² / (0.04 - x)²

√0.10 = 2x / (0.04 - x)

(√0.10) (0.04 - x) = 2x

(√0.10)(0.04) - (√0.10)x = 2x

(√0.10)(0.04) = 2x + (√0.10)x

(√0.10)(0.04) = (2 + √0.10)x

x = (√0.10)(0.04) / (2 + √0.10)

x = 0.0055

At equilibrium, the concentration of NO is 2x. So the answer is:

[NO] = 2x

[NO] = 0.011

The equilibrium concentration of NO is 0.011 mol/L.

3 0

3 years ago

Calculate the oxidation number of “C” in CH3COCH3 please

Triss [41]

Answer:

The oxidation number of C (carbon) is +4

Explanation:

8 0

4 years ago

In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 gram

kherson [118]

This question is incomplete, the complete question is;

In recrystallization from boiling water of benzoic acid contaminated with acetanilide, you begin with an impure sample of 5 grams. If the % composition of the acetanilide impurity in the sample is 6.3 %, what is the minimum amount in mL of solvent (water) required for the recrystallization

Compound Solubility in water at 25°C Solubility in water at 100°C

Benzoic Acid 0.34 g/100mL 5.6 g/100mL

Acetanilide 0.53 g/100mL 5.5 g/100mL

Answer:

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

Explanation:

Given the data in the question;

mass of sample = 5 g

percentage composition of the acetanilide impurity = 6.3%

mass of the acetanilide in impure sample will be;

⇒ 6.3% × 5 g = 0.315 g

Mass of benzoic acid in impure sample;

⇒ 5 g - 0.315 g = 4.685 g

now, solubility in water at 100°C for benzoic acid = 5.6 g/100mL

hence 4.685 g of benzoic acid is soluble in x mL

x = [ 100 mL × 4.685 g ] / 5.6 g

x = 83.66 ≈ 84 mL

Also, solubility in water at 100°C for acetanilide = 5.5 g/100mL

hence 0.315 g of benzoic acid is soluble in x mL

x = [ 100 mL × 0.315 g ] / 5.5 g

x = 5.727 ≈ 6 mL

So, the minimum amount in mL of solvent (water) required for the recrystallization will be;

⇒ 85 mL + 6 mL = 91 mL

The minimum amount in mL of solvent (water) required for the recrystallization is 91 mL

5 0

3 years ago

What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin

beks73 [17]

Answer:

$\boxed{\text{2 mol/L}}$

Step-by-step explanation:

$c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }$

Data:

n = 5 mol

V = 2.5 L

Calculation:

$c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}$

The molar concentration of the solution is $\boxed{\textbf{2 mol/L}}$ .

6 0

3 years ago