Answer:
See explanation below
Explanation:
You are not providing the starting material, however, I manage to find a similar question to this, so I'm gonna use it as a basis to help you answer yours.
Now let's analyze what is happening in the reaction so we can predict the final product.
We have a ketone here, reacting at first with LDA. This is a very strong base that is commonly used in reactions with ketones and aldehydes to promove a condensation. To do this, as LDA is a strong base it will occur firts an acid base reaction, substracting the most acidic hydrogen in the molecule (Which in this case, is the Beta hydrogen of the carbonile). This will cause an enolate formation.
Then, this enolate will react with the CH3I and form a new product. The final result would be a ketone with a methyl group now attached. In the picture 2, you have the mechanism and final product.
Hope this helps
Answer
<span>How does adding a non-volatile solute to a pure solvent affect the vapor pressure of the pure solvent?
</span>Answer The third option The solvent's vapor pressure will not be affected.
<span>To make a 2.0 M solution, how many moles of solute must be dissolved in 0.50 liters of solution?
Answer C. 1.0 mole solute.
</span>
Answer:
(D) Neither I nor II
Explanation:
The reagent potassium hydrogen phthalate is found in pure form and it is not partially hydrated .
The pallet form of NaOH ( solid form ) absorbs carbon dioxide gas from the atmosphere but NaOH in solution form does not absorb carbon dioxide .
Hence option D ) is right choice .
The correct answer is 2.70 × 10² g or 270 g.
It is given, that the density of a metal is 9.80 g/ml.
Let the mass of a sample of metal be x.
The sample of metal is dropped in 28.9 ml of water, due to which the volume of the water increases to 56.4 ml.
In order to calculate the mass of a metal, there is a need to use the formula, mass = density * volume
Mass = (9.80 g/ml) (56.4 ml - 28.9 ml)
= (9.80 g/ml) (27.5 ml)
= 2.70 × 10² g or 270 g
Answer:
Water is made of two ___hydrogen_ atoms and one ____oxygen_ atom.