Answer:
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Explanation:
Solubility of solute at 20°C = 32.2 g/100 grams of water
Solute soluble in 1 gram of water = 
Mass of solute in soluble in 56.0 grams of water:

Solubility of solute at 30°C = 70.2g/100 grams of water
Solute soluble in 1 gram of water = 
Mass of solute in soluble in 56.0 grams of water:

If the temperature of saturated solution of this solute using 56.0 g of water at 20.0 °C raised to 30.0°C
Mass of solute in soluble in 56.0 grams of water 20.0°C = 18.032 g
Mass of solute in soluble in 56.0 grams of water at 30.0°C = 39.312 g
Mass of of solute added If the temperature of the saturated solution increased to 30.0°C:
39.312 g - 18.032 g = 21.28 g
21.28 grams solute can be added if the temperature is increased to 30.0°C.
Answer:
The correct answer is 930 grams platelets.
Explanation:
The volume of blood given is 1.89 pints. Total number of gallons in 1.89 pints is,
= 1.89/8 = 0.236 gallon
1 gallon comprise = 3.785 L
So, 0.236 gallon comprise = 0.236 * 3.785 L = 0.89 L
As mentioned that 1 Liter of blood comprise 1.04 kilograms of platelets. Therefore, 0.89 L of blood will contain = 1.04 * 0.89 = 0.93 Kg platelets
1 Kg contain 1000 grams. So, number of platelets in grams will be,
= 1000 * 0.93 = 930 grams platelets.
Answer:
Krypton.
Explanation:
By Graham's Law:
Rate 1 / Rate 2 = sqrt M2 / sqrt M1
Molecular Mass for Neon is 20.18
so we have:
38 / 77.5 = sqrt 20.18 / sqrt x where x is the unkown gas.
sqrt x = 9.162
x = 83.94.
This gas is Krypton.
Answer:
Explanation:
The
has 22 electrons arround the nucleous. Its ground state configuration following the diagonal rule is:
In term of the previous noble gas:
According to the kinetic theory, the mean free path is the average distance a single atom or molecule of an element or compound travels with respect with the other atoms during a collision. The greater the mean free path, the more ideal the behavior of a gas molecule is because intermolecular forces are minimum. To understand which factors affect the mean free path, the equation is written below.
l = μ/P * √(πkT/2m), where
l is the mean free path
μ is the viscosity of the fluid
P is the pressure
k is the Boltzmann's constant
T is the absolute temperature
m is the molar mass
So, here are the general effects of the factors on the mean free path:
Mean free path increases when:
1. The fluid is viscous (↑μ)
2. At low pressures (↓P)
3. At high temperatures (↑T)
4. Very light masses (↓m)
The opposite is also true for when the mean free path decreases. Factors that are not found here have little or no effect.