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antiseptic1488 [7]
3 years ago
9

How many atoms are ln 6.31 moI of sodium sulfate

Chemistry
2 answers:
Art [367]3 years ago
6 0
896.27
One mole of sodium sulfate is 143.04, so just multiply that times 6.31.
I may be wrong call me out if I am
Murrr4er [49]3 years ago
6 0
896.27

6.31 sodium/ sulfate//// 896.27 ///
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When an organic molecule loses hydrogen atoms it is said to be:_______.
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How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
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Answer:

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PV = nRT

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We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

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R = 0.08206L.atm/mol.K

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Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

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n = PV/RT

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n = 1.0834112811moles

Step 2

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41.169628682grams

Approximately = 41.17 grams.

3 0
3 years ago
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