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antiseptic1488 [7]
3 years ago
9

How many atoms are ln 6.31 moI of sodium sulfate

Chemistry
2 answers:
Art [367]3 years ago
6 0
896.27
One mole of sodium sulfate is 143.04, so just multiply that times 6.31.
I may be wrong call me out if I am
Murrr4er [49]3 years ago
6 0
896.27

6.31 sodium/ sulfate//// 896.27 ///
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E. HCl

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Brainliest! a. Write a short historical account of the discovery of the Avogadro’s number.
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Task 2

a.

Percent composition is the percent by mass of each element present in a compound. Water, H2O, is the first example. One mole of water is 18.0152 grams. In that compound, there are two moles of H atoms and 2 x 1.008 = 2.016 grams. That's how many grams of hydrogen are present in one mole of water. this is an example. i don't know what you are describing though. i need more info for this question

b. 6.022 to 6.023 x 10^23

c. i don't know what this one is since there is nothing to describe the unknown liquid.

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Explanation:

4 0
3 years ago
As the [ht] in a solution decreases, what happens to the [OH???
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Why you saying we can download an answer we’re here for an answer
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What is the name of CH3CH(OH)CH2CH2CH3?
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3 0
3 years ago
PD-99 has a half-life of 22.3 hours. How many grams of a 89.8 gram sample would have decayed after exactly three half-lives?
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Answer:

78.875 g

Explanation:

First half life is the time at which the concentration of the reactant reduced to half.

Second half reaction is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/4.

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<u>So, the mass of the sample decayed = 89.8 g - 11.225 g = 78.875 g</u>

4 0
3 years ago
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