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vagabundo [1.1K]
3 years ago
14

What is/are the organization's prey?

Chemistry
1 answer:
natka813 [3]3 years ago
4 0

Answer:

Nearly 80 per cent of organisations in North America and Europe were victims of cyber attacks last year and nearly half of cyber attacks used malware hidden in encrypted traffic to evade detection, a report said on Wednesday.

The encryption technology that is crucial to protecting sensitive data in transit such as web transactions, emails and mobile apps, can allow malware hiding inside that encrypted traffic to pass uninspected through an organisation’s security framework.

The report by US-based security company A10 Networks in partnership with Ponemon Institute surveyed 1,023 IT and IT security practitioners in North America and Europe, highlighting the challenges these professionals face in preventing and detecting cyber attacks.

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Indicate whether the following are acidic, basic, or neutral solution
goldenfox [79]
You answer this by using the pH formula and and the relation of pH and pOH, pH = -log[H+] and 14 = pH + pOH. The correct classification are as follows:

<span>A. [H2O+]=6.0x10^-12
basic

B. [H3O+]=1.4x10^-9
basic

C. [OH-]=5.0x10^-12
acidic

D. {OH-]=3.5x10^-10
acidic

Hope this answers the question.

</span>
5 0
2 years ago
Protons, neutrons, and electrons all have similar masses. explain why this statement is false.
yan [13]
It is false because electrons have no mass.
6 0
2 years ago
DONT SKIPP What type of bond will occur between lithium and bromine?
den301095 [7]
An ionic bond is formed between lithium and bromine.
4 0
3 years ago
G vinegar is a solution of acetic acid in water. if a 165 ml bottle of distilled vinegar contains 28.2 ml of acetic acid, what i
Delicious77 [7]
<span>Volume Percent (volume/volume%) is defined to be the ratio of the volume of solute to the volume of solution times 100%. The acetic acid is the solute volume. The bottle of vinegar is the solution volume. Acetic acid (28.2ml) / Vinegar(165ml) x 100% = 17.1%</span>
7 0
3 years ago
A volume of 90.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Alja [10]

Answer:

0.823 M was the molarity of the KOH solution.

Explanation:

H_2SO_4+KOH\rightarrow K_2SO_4+2H_2O (Neutralization reaction)

To calculate the concentration of base , we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50 M\\V_1=24.7 mL\\n_2=1\\M_2=?\\V_2=90.0 mL

Putting values in above equation, we get:

2\times \1.50 M\times 24.7 mL=1\times M_2\times 90.0 mL

M_2=\frac{2\times 1.50M\times 24.7 mL}{1\times 90.0 mL}=0.823 M

0.823 M was the molarity of the KOH solution.

7 0
3 years ago
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