You answer this by using the pH formula and and the relation of pH and pOH, pH = -log[H+] and 14 = pH + pOH. The correct classification are as follows:
<span>A. [H2O+]=6.0x10^-12
basic
B. [H3O+]=1.4x10^-9
basic
C. [OH-]=5.0x10^-12
acidic
D. {OH-]=3.5x10^-10
acidic
Hope this answers the question.
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It is false because electrons have no mass.
An ionic bond is formed between lithium and bromine.
<span>Volume Percent (volume/volume%) is defined to be the ratio of the volume of solute to the volume of solution times 100%.
The acetic acid is the solute volume. The bottle of vinegar is the solution volume.
Acetic acid (28.2ml) / Vinegar(165ml) x 100% = 17.1%</span>
Answer:
0.823 M was the molarity of the KOH solution.
Explanation:
(Neutralization reaction)
To calculate the concentration of base , we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:

Putting values in above equation, we get:


0.823 M was the molarity of the KOH solution.