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3 years ago

What is the recommended heart rate for a 20 year old person?

Mathematics

2 answers:

dlinn [17]3 years ago

4 0

Answer:

The average maximum heart rate for a 20 year old is 200 bpm

The target heart rate is 100-170 beats per minute (bpm).

I Hope this helps and I hope everything is okay!

lions [1.4K]3 years ago

4 0

200 bpm ( beats per minute)
Hope this helps

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4X Takeaway 10 equals 20+ 6X

Natasha2012 [34]

X= -15
First, we want to combine like terms.
4x-10=20+6x
Subtract 4x from both sides
-10=20+2x
Subtract 20 from both sides
-30=2x
Divide by 2 to isolate the variable
X= -15

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4 years ago

Find the slope of the line that passes through (8, 4) and (2, 9).

Alekssandra [29.7K]

The answers is not -5/6

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3 years ago

Can you solve ? |2x-9|=7 What is the answer please

Nikitich [7]

Split it into 2 equations
2x-9 = 7
2x = 16
x = 8
And another equation
2x-9 = -7
2x = 2
x = 1
The answer is x =1, x= 8

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3 years ago

A street light is at the top of a 11 ft tall pole. A woman 6 ft tall walks away from the pole with a speed of 7 ft/sec along a s

zheka24 [161]

Answer:

The answer is 8.5 Ft/Sec.

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

Step-by-step explanation:

The tip of the woman's shadow is moves from the base of the pole when she is 50ft away at the speed of 8.5 Ft/Sec

The solution and explanation is attached.

Download pdf

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3 years ago

A mass oscillating up and down on the bottom of a spring can be modeled as harmonic motion. if they weight is displaced a maximu

snow_tiger [21]

9514 1404 393

Answer:

1.63 cm (across the centerline from release)

Step-by-step explanation:

If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...

h(t) = -7cos(2πt/4)

h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm

That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.

If it is released from above the resting position, it will be 1.63 cm below the resting position at t=1.15 seconds.

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3 years ago