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ratelena [41]
3 years ago
10

Shelby travels 6 meters East, 2 meters North, 3 meters West, and then 2 meters South. What is their displacement?

Physics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

3 m

Explanation:

At last, Same line; so, 6-3 = 3

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A 0.0450 kg bullet is accelerated from rest to a speed of 425 m/s in a 2.25 kg rifle (which is inititally at rest). The pain of
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Answer:

If the rifle is held loosely away from the shoulder, the recoil velocity will be of -8.5 m/s, and the kinetic energy the rifle gains will be 81.28 J.

Explanation:

By momentum conservation, <em>and given the bullit and the recoil are in a straight line</em>, the momentum analysis will be <em>unidimentional</em>. As the initial momentum is equal to zero (the masses are at rest), we have that the final momentum equals zero, so

0=P_{f}=m_{b} *v_{b}+m_{r}*v_{r}

now we clear v_{r} and use the given data to get that

v_{r}=-8.5\frac{m}{s}

<em>But we have to keep in mind that the bullit accelerate from rest to a speed of 425 m/s</em>, then <u>if the rifle were against the shoulder, the recoil velocity would be a fraction of the result obtained</u>, but, as the gun is a few centimeters away from the shoulder, it is assumed that the bullit get to its final velocity, so the kick of the gun, gets to its final velocity \bold{v_{r}} too.

Finally, using v_{r} we calculate the kinetic energy as

K=\frac{1}{2}m_{r}v_{r}^{2}=81.28J

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Answer:

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For a steady two-dimensional flow the boundary layer approximations are The velocity component in the flow direction is much larger than that in the normal direction and The temperature and velocity gradients normal to the flow are much greater than those along the flow direction

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