1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
8090 [49]
3 years ago
15

Given 5.0 grams of lead (II) nitrate and 3.0

Chemistry
1 answer:
natulia [17]3 years ago
7 0

Answer:

                     1.70 g of NaNO₃

Explanation:

                     The balance chemical equation for given double displacement reaction is,

                               Pb(NO₃)₂ + 2 NaI → PbI₂ + 2 NaNO₃

Step 1: <u>Calculate moles of each reactant:</u>

                                   Moles =  Mass / M.Mass

For Pb(NO₃)₂:

                                   Moles =  5.0 g / 331.21 g/mol

                                   Moles =  0.0150 moles

For NaI:

                                   Moles =  3.0 g / 149.89 g/mol

                                   Moles =  0.020 moles

Step 2: <u>Calculate Limiting reagent as;</u>

According to equation,

                     1 mole of Pb(NO₃)₂ reacts with  =  2 moles of NaI

So,

              0.0150 moles of Pb(NO₃)₂ will react with  =  X moles of NaI

Solving for X,

                     X =  2 mol × 0.0150 mol / 1 mol

                     X =  0.030 moles of NaI

Hence, it means that NaI is the limiting reagent therefore, it will control the yield of Sodium Nitrate.

Step 3: <u>Find out moles of NaNO₃ formed:</u>

According to equation,

                     2 mole of NaI produced =  2 moles of NaNO₃

So,

              0.020 moles of NaI will produce   =  X moles of NaNO₃

Solving for X,

                     X =  2 mol × 0.020 mol / 2 mol

                     X =  0.020 moles of NaNO₃

Step 4: <u>Calculate Mass of NaNO₃ produced;</u>

As,                Moles  =  Mass / M.Mass

Or,

                    Mass  =  Moles × M.Mass

Putting values,

                    Mass  =  0.020 mol × 84.99 g/mol

                    Mass  =  1.70 g of NaNO₃

You might be interested in
What are 2 mixtures and explain your answer
liq [111]
Water and orange juice
Or orange juice and sodium chloride
3 0
3 years ago
True or false. When an area within an atom is crowded with electrons it is known as a dipole "moment False True
Rama09 [41]

Answer:true

Explanation:

4 0
2 years ago
Read 2 more answers
Where can I get a oxygen isotope analysis comercialy
miskamm [114]

Answer:

Honestly I don't know.

Explanation:

Haha good luck though

6 0
3 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
Why is it useful to know the background level of extinction?
lawyer [7]

Answer:

NOAA and FWS are required by law to compare background rates to current rates.

Explanation:

5 0
2 years ago
Other questions:
  • According to a label on a bottle of concentrated hydrochloric acid, the contents are 36.0% HCl by mass and have a density of 1.1
    11·1 answer
  • The following atoms are all variations of the element carbon: 12C, 13C, and 14C due to differing
    15·1 answer
  • In the following chemical reaction, how many moles of N2 are needed to completely react with 3 moles of H2? N2 + 3 H2 2 NH3
    7·2 answers
  • \The specific heat of aluminum is 0.21 cal g°C . How much heat is released when a 10 gram piece of aluminum foil is taken out of
    11·1 answer
  • Which is an anion ca2+ ag+ o2- k+
    12·2 answers
  • The lymphatic system collects<br> While in<br> the lymphatic system, the fluid<br> is called
    7·1 answer
  • Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.
    7·1 answer
  • What geological forces might be responsible for this range of mountains?
    6·1 answer
  • HELP FAST PLZ!!!!!!!!!!!!!_____ energy from the outlet transfers energy to the light bulband
    15·2 answers
  • . Which laboratory equipment would most likely be used for testing a substance for the presence of monosaccharides? *
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!