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myrzilka [38]
3 years ago
9

True or false. When an area within an atom is crowded with electrons it is known as a dipole "moment False True

Chemistry
2 answers:
marishachu [46]3 years ago
8 0

Answer:

im not sure but ill say false

Explanation:

Rama09 [41]3 years ago
4 0

Answer:true

Explanation:

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Which of the following information can be determined from this isotope: sodium 23 and why?
JulsSmile [24]

<h2>YOUR ANSWER Is number of istopes</h2>

✌️

4 0
3 years ago
Rachel loves gardening. This summer, her 10 ft x 10 ft garden space is divided equally among tomatoes, lettuce, and strawberries
Ray Of Light [21]

Answer:

Rachel needs 0.52 kg of fertilizer.

Explanation:

Since the surface is a <em>square</em> of 10 ft of size its area is A = 10 ft x 10 ft = 1.0 x 10² ft². <em>One third</em> of that space is devoted to tomatoes (<em>"space is divided equally among tomatoes, lettuce, and strawberries"</em>), that is, 1/3 x 100 ft² = 33 ft².

We calculate the kilograms of fertilizer required we need to know 2 equivalences:

1 ac = 43,560 ft²

1 lb = 0.4535 kg

Then, we can use proportions to find out the amount of fertilizer used:

33ft^{2} \frac{1ac}{43,560ft^{2} } .\frac{1,500lb}{1ac} .\frac{0.4535kg}{1lb} =0.52kg

7 0
3 years ago
In class we derived the Gibbs energy of mixing for a binary mixture of perfect gases. We also discussed that the same result is
GaryK [48]

Answer:

Attached below

Explanation:

Free energy of mixing = ΔGmix = Gf - Gi

attached below is the required derivation of the

<u>a) Molar Gibbs energy of mixing</u>

ΔGmix = Gf - Gi

hence : ΔGmix = ∩RT ( X1 In X1 + X2 In X2 + X3 In X3 + ------- )

<u>b) molar excess Gibbs energy of mixing</u>

Ni = chemical potential of gas

fi = Fugacity

N°i = Chemical potential of gas when Fugacity = 1

ΔG = RT In ( a2 / a1 )  

4 0
3 years ago
a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.
Alex17521 [72]

Answer:

m_{Co}=6998g=7.0kg

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})

Thus, we solve for the mass of cobalt as shown below:

m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg

Best regards!

7 0
3 years ago
HELP I think its C but I'm not sure
nasty-shy [4]
The answer is A. Mars

4 0
3 years ago
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