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myrzilka [38]
3 years ago
9

True or false. When an area within an atom is crowded with electrons it is known as a dipole "moment False True

Chemistry
2 answers:
marishachu [46]3 years ago
8 0

Answer:

im not sure but ill say false

Explanation:

Rama09 [41]3 years ago
4 0

Answer:true

Explanation:

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Why water can be unsafe in a pool?
Evgen [1.6K]

Answer:People can drown or call or slip in

Explanation:

7 0
3 years ago
Read 2 more answers
How many significant figures are there in the measurement 64,000 mg?
DedPeter [7]
For sig figs, you count the total number of numbers that aren’t 0, you only count 0 if they are after a decimal point. since there is not a decimal point, there are 2 significant figures, answer A
3 0
3 years ago
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Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.
Dmitriy789 [7]
N₂H₄  +  2H₂O₂    →   N₂  +  4H₂O

mol = mass ÷ molar mass

If mass of hydrazine (N₂H₄)  = 5.29 g 
then mol of hydrazine           = 5.29 g ÷ ((14 ×2) + (1 × 4))
                                              = 0.165 mol

mole ratio of hydrazine to Nitogen is     1   :  1
  ∴ if moles of hydrazine = 0.165 mol
     then moles of nitrogen = 0.165 mol

Mass = mol × molar mass

Since mol of nitrogen (N₂)  = 0.165
then mass of hydrazine      = 0.165 × (14 × 2)
                                           = 4.62 g
5 0
3 years ago
At a certain temperature this reaction follows first-order kinetics with a rate constant of 2.01 s^−1
ddd [48]

Answer:

0.80 seconds (2 significant figures)

Explanation:

The equation of the reaction is given as;

CICH2CH2Cl (g) --> CH2CHCI (g) + HCl(g)

Rate constant (k) = 2.01 s^-1

From the units of the rate constant, this is a first order reaction.

Initial Concentration = 1.34 M

t = ?

Final concentration = 20% of 1.34 = 0.268 M

The integrated rate law for a first order reaction is given as;

ln[A] = ln[A]o - kt

ln(0.268) = ln(1.34) - 2.01(t)

-2.01(t) = - 1.6094

t = 0.8007 ≈ 0.80 seconds (2 significant figures)

6 0
3 years ago
499 mg sample of CuSO4. xH2O is heated and reweighed to give a mass of 319 mg. Given that the sample contains 2 mmol of Cu; what
nevsk [136]

The value of x in CuSO4. xH2O is 5.

Given that;

Number of moles of anhydrous salt = Number of moles of hydrated salt

Number of moles of anhydrous salt = 319 × 10^-3

Mass of hydrated salt = 499 ×10^-3 g

Number of moles of anhydrous salt = 319 10^-3g/160 g/mol = 0.00199 moles

Number of moles of hydrated salt = 499 × 10^-3 g/ 160 + 18x

0.00199 =  499 × 10^-3 g/ 160 + 18x

0.00199 (160 + 18x) = 499 ×10^-3

0.318 + 0.036x = 0.499

0.036x = 0.499 - 0.318

0.036x = 0.181

x = 0.181/0.036

x = 5

Hence,  x in CuSO4. xH2O is 5.

Learn more: brainly.com/question/9743981

8 0
3 years ago
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