Which of the following compounds has the lowest percent gold content by weight?
1 answer:
Compounds have the lowest percentage of gold content by weight is <u>Aui3</u>
M(Au) =197g/mol
M(O) =16g/mol
M(H)=1g/mol
M(Cl)=35g/mol
M(I)=53 g/mol
1) M=214g/mol =197+1+16
197/214= 0.921
2) M=248g/mol =
197/248=0.794
3) M=302g/mol =
197/302=0.652
4) M=356g/mol =
197/356=0.5533
<u>Explanation:</u>
Iodine is the heaviest out of I, Cl and OH. The items on your list hold less and less gold by mass as you go down. The gold dissolution percentage in a hypochlorite-iodide mix-up is completely conditioned upon the solution pH. So the iodine has the lowest gold content percentage.
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Answer:
5.82 L
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 2.25 L
V₂ = ?
P₁ = 2.7 atm
T₁ = 12 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
At STP, Pressure = 1 atm and Temperature = 273.15 K
So,
P₂ = 1 atm
T₂ = 273.15 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 5.82 L</u>
Answer:
The gold gains a total of 2.468 kilo-joules of energy.
Explanation:
Total heat or energy gained by the gold is equal to heat applied and heat required to melt the gold completely.
Total energy = Q+ Q'
Heat of fusion of gold =
Mass of gold melted ,m= 12.5 g
Specific heat of gold ,c= 0.1291 joules/gram °C
Change in temperature = ΔT = 1064°C - 26°C = 1038 °C
Heat of applied to the gold = Q
Total energy = Q+ Q'
= 2,468.82 Joule= 2.468 kilo-Joule
The gold gains a total of 2.468 kilo-joules of energy.