Please I need help with the question 42 and answering the chart and it’s very hard and I’m struggling with it and if you need to
see the picture big then click on it and it will be big
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The integrated rate law for a second-order reaction is given by:
where, [A]t= the concentration of A at time t,
[A]0= the concentration of A at time t=0
<span>k =</span> the rate constant for the reaction
<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min
Hence,
<span> = 4.858</span>
<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>
<span>
</span>
<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M
The drawing is correct because there are 12 atoms of each type on each side of the arrow.
