A right isosceles triangle has an area of 65cm^2. What's the length of each leg to the nearest tenth of a cm.

1 answer:

5 0

Well, we know that the legs of this triangle are equal, and we know
that the area of any triangle is (1/2)(base)(height) .

Since this is a right triangle, we can set it down on one leg, and then
the other leg will be the height. Then ...

Area = (1/2) (base) (height)

= (1/2) (leg) (leg)

65 cm² = (1/2) (leg)²

Multiply each side by 2 : 130 cm² = (leg)²

Take the square root of each side: leg = √130 cm² = 11.402 cm

rounded to the nearest tenth: 11.4 cm

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Whitepunk [10]

Hi there!

Question 1:

For this, we are taking away 1/4 yards of spring from 7/8 yards. This is essentially just subtracting 1/4 from 7/8. This then gives us the equation:

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Question 2:

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