Answer:
See explanation.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
<u>Calculus</u>
Limits
- Right-Side Limit:

- Left-Side Limit:

Limit Rule [Variable Direct Substitution]: 
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Find Right Limit</u>
- Substitute in variables [Right-Side Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

- Subtract:

∴ the right-side limit equals 2.
<u>Step 3: Find Left Limit</u>
- Substitute in variables [Left-Side Limit]:

- Evaluate limit [Limit Rule - Variable Direct Substitution]:

- [√Radical] Add:

- [√Radical] Evaluate:

∴ the left-side limit equals 2.
<u>Step 4: Find Limit</u>
<em>The right and left-side limits are equal.</em>
∴ 
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
Book: College Calculus 10e
Answer:
a.) x = -1/3
b.) 8
c.) 6
d.) 8
e.) 6
Step-by-step explanation:
The place value of the underlined number is the thousands place.
Answer: 0.205
Step-by-step explanation:
The probability in one flip is equal to 0.5.
Now, if we do 10 flips, we want 4 times that the coin ends in heads and the other 6 times it must end in tails, so the probability is:
0.5^4*0.5^6 = 0.5^10
Now, this is the case where in the first 4 flips we get heads and in the other 6 we get tails, but we have other ways to get only 4 heads (for example in the last 4 flips, 2 at the beginning and 2 at the end, etc)
So we also need to calculate all the possible permutations of 4 heads in 10 flips. this is:
C = 10!/(10 - 4)!*4! = (10*9*8*7)/(4*3*2*1) = 210
So the probability that we are looking for is:
P = (0.5^10)*210 = 0.205
Answer:
$73.25
Step-by-step explanation:
35 + 2.55(15) = 38.25 + 35 = 73.25