Answer:
68 grams
Explanation:
Reaction that produces ammonia when nitrogen and hydrogen reacts is given by :-
+ 3 → 2N
Clearly ,
When one mole of nitrogen reacts , two moles of ammonia will be produced.
Now,
weight of 1 mole of the Nitrogen = 28.0 grams
In 56.0 grams of the nitrogen , two moles will be present.
Thus , 4 moles of ammonia will be produced .
Weight of one mole of nitrogen = 17 grams.
Thus a total of 17× 4 = 68 grams f nitrogen will be produced.
Answer:
87.9%
Explanation:
Balanced Chemical Equation:
HCl + NaOH = NaCl + H2O
We are Given:
Mass of H2O = 9.17 g
Mass of HCl = 21.1 g
Mass of NaOH = 43.6 g
First, calculate the moles of both HCl and NaOH:
Moles of HCl: 21.1 g of HCl x 1 mole of HCl/36.46 g of HCl = 0.579 moles
Moles of NaOH: 43.6 g of NaOH x 1 mole of NaOH/40.00 g of NaOH = 1.09 moles
Here you calculate the mole of H2O from the moles of both HCl and NaOH using the balanced chemical equation:
Moles of H2O from the moles of HCl: 0.579 moles of HCl x 1 mole of H2O/1 mole of HCl = 0.579 moles
Moles of H2O from the moles of NaOH: 1.09 moles of HCl x 1 mole of H2O/1 mole of NaOH = 1.09 moles
From the calculations above, we can see that the limiting reagent is HCl because it produced the lower amount of moles of H2O. Therefore, we use 0.579 moles and NOT 1.09 moles to calculate the mass of H2O:
Mass of H2O: 0.579 moles of H2O x 18.02 g of H2O/1 mole of H2O = 10.43 g
% yield of H2O = actual yield/theoretical yield x 100= 9.17 g/10.43 g x 100 = 87.9%
Molecules move from areas of low concentration to areas of high concentration. This requires the use of energy.
Answer:
9.62 × 10² J
Explanation:
In this problem, we need to convert 230 calories to joules. For this, we must know the conversion from calories to joules.
1 Calorie = 4.184 Joules
To find Joules in 230 calories, multiply 4.184 by 23. So,
230 Calorie = (230 × 4.184) Joules
= 962.32 Joules
or
230 Calories = 9.62 × 10² J
So, the correct option is (A).