Question:
The relative humidity of air equals the ratio of the partial pressure of water in the air to the equilibrium vapor pressure of water at the same temperature times 100%. If the relative humidity of the air is 58% and its temperature is 68 oF , how many moles of water are present in a room measuring 12 ft x 10 ft x 8 ft?
Answer:
15.1379 moles of water are present in a room measuring 12 ft x 10 ft x 8 ft.
Explanation:
Given:
Relative humidity of the air = 58%
Temperature =
To Find:
Number of moles of water are present in a room measuring 12 ft x 10 ft x 8 ft = ?
Solution:
Converting temperature Fahrenheit to Celsius
The vapour pressure of is equal to 17.54 torr
vapour pressure of air
= torr
= 10.17132 torr
Volume of the room =
=>
=>
Using the ideal gas equation
PV = nRT
Volume in Litres = 27184.2 L
Pressure in atm
=
= 0.0133945 atm
Now substituting the values we get
Pv = nRT
n = 15.1379 moles
Answer:
C4H9OH + 6O2 → 4CO2 + 5H2O
Explanation:
Answer:
.055 mol/L
Explanation:
Henry's Law is about solubility of a gas in a liquid which is dependent on the partial pressure of gas above the liquid . According to it
C = k P where C is concentration of gas in the liquid , k is henry's constant and P is partial pressure of the gas .
Given k = .159 mol/L.atm
P = 265 mm of Hg
= 265 / 760
= .34868 atm
C = kP
= .159 x .34868
= .055 mol/L
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