Answer:
Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.
Some of the chemical changes used by the industrial chemist in order to identify it is by inserting it in water to observe that whether it reacts with it or not, if the reaction is violent, then the metal belongs to either group I or group II. The other method is to insert it in acids of distinct strength and to observe its reaction. The metals belonging to the second group react briskly with acids. The other metals react gradually with acids and others are almost inert.
B. The area of the island is your answer :)
Baking soda is sodium bicarbonate in anhydrous form without any water of crystallisation and it is widely used as dry fire extinguisher because of its alkali nature.
Answer:
25 g/hr
Explanation:
Remember that the rate of reaction refers to the rate at which reactants are used up or or the rate at which products appear.
Hence;
Rate of reaction = mass of reactant used up/time taken
Mass of reactant used up= 2g
Time taken = 5 minutes or 0.08 hours
Rate of reaction = 2g/0.08 hours = 25 g/hr
To find the rate constant we can write a rate expression for the following reaction:
2A + B → C
A rate expression is written as some rate constant multiplied by the concentrations of the reactants, with each concentration raised to the power of the molar coefficient. [A] has a coefficient of 2, and [B] has a coefficient of 1. Therefore, we get the following rate expression:
rate = k[A]²[B]
We are given a table of values and we can enter the three variable to solve for k.
k = (rate)/([A]²[B])
k = (0.035)/((0.05)²(0.05))
k = 280
We can confirm if the value for k is correct by using another set of concentrations, along with the rate constant and solve for the rate.
rate = 280 [0.10]²[0.05]
rate = 280 (0.01)(0.05)
rate = 0.14
The value we solved for agrees with the rate provided in the table, therefore we know our value for the rate constant is correct which is k = 280.
