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3 years ago

Oxygen and sulfur are both in the family

1 answer:

8 0

On the periodic table, sulfur belongs to group 16, which is the chalcogen group or the oxygen family. This family contains oxygen, sulfur, selenium, tellurium and polonium.

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The balanced chemical equation for the complete combustion propane, C3H8 is: C3H8 + 5O2 → 3CO2 + 4 H2O How many moles of H2O wou

BartSMP [9]

4/5 × 0.200 moles= 0.160moles

8 0

3 years ago

Jones Soda contains 33g added sugar (C6H12O6) in a 355 ml bottle, while Sierra Mist contains 62g added sugar in a 591 ml bottle.

ArbitrLikvidat [17]

C6H12O6 molar mass: 180.15768 g

solute: sugar

molarity = moles of solute / liters of solution

Jones Soda:

33 g / 180.15768 g = 0.18 moles C6H12O6

M = 0.18 g / 0.355 L

M = 0.52

Sierra Mist:

62 g / 180.15768 g = 0.34 moles C6H12O6

M = 0.34 g / 0.591 L

M = 0.58

Sienna Mist has a higher molarity and is more concentrated.

7 0

3 years ago

Consider two different ions. The anion has a valence of -2. The cation has a valence of +2. The two ions are separated by a dist

strojnjashka [21]

Answer:

Force of attraction = 35.96 $\times 10^{27}$ N

Explanation:

Given: charge on anion = -2

Charge on cation = +2

Distance = 1 nm = $10^{-9}$ m

To calculate: Force of attraction.

Solution: The force of attraction is calculated by using equation,

$F = \dfrac{k \times q_1 q_2}{ \r^2}$ ---(1)

where, q represents the charge and the subscripts 1 and 2 represents cation and anion.

k = $8.99 \times 10^9 \ Nm^{2}C^{-2}$

F = force of attraction

r = distance between ions.

Substituting all the values in the equation (1) the equation becomes

$F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }$

Force of attraction = 35.96 $\times 10^{27}$ N

6 0

2 years ago

Upper n subscript 2 (g) plus 3 upper H subscript 2 (g) double-headed arrow 2 upper N upper H subscript 3 (g). At equilibrium, th

artcher [175]

Answer:

The <u>equilibrium constant</u> is:

$k_c=0.0030M^{-2}$

Explanation:

The correct equation is:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

Thus, with the equilibrium concentrations you can calculate the equilibrium constant, Kc.

The equation for the equilibrium constant is:

$k_c=\dfrac{[NH_3]^2}{[N_2]\cdot [H_2]^3}$

Substituting:

$k_c=\dfrac{(0.105M)^2}{(1.1M)\cdot (1.50M)^3}$

$k_c=0.0030M^{-2}$

6 0

3 years ago

Consider an element Z that has two naturally occuring isotopes with the following percent abundances: the isotope with a mass nu

rodikova [14]

Answer:

Z=22.70

Explanation:

It is given that,

An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.

The average atomic mass for element Z is given by :

$Z=\dfrac{22\times 65+24\times 35}{100}\\\\Z=22.7$

So, the average atomic mass for element Z is 22.70.

3 0

3 years ago