Answer:
The initial temperature is 300 K (The temperature doesn't change)
Explanation:
Step 1: Data given
Initial volume = 21L
Final volume = 14L
Initial pressure = 100 kPa = 0.986923 atm
Final pressure = 150 kPa = 1.48038 atm
The final temperature = 300K
Step 2: Calculate the initial temperature
Calculate the initial temperature
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 0.986923 atm
⇒with V1 = the initial volume = 21 L
⇒ with T1 = the initial temperature = ?
⇒with P2 = the final pressure = 1.48038 atm
⇒with V2 = the final volume = 14 L
⇒with T2 = the final temperature = 300 K
(0.986923 * 21)/T1 = (1.48038*14)/300
T1 = 300 K
The initial temperature is 300 K (The temperature doesn't change)
When a nucleus emits a positron, its atomic number is lowered by one but its mass number stays the same.
1st law states that energy cannot be created or destroyed in an isolated system hence the answer is the heat that flows into the system is transformed into work and change in internal energy....
...I think that the answer
Answer:
Explanation:
Given
Required
Determine the area
The area of a triangle is :
By substituting values for the x and y coordinates of A, B and C;
We have:
So:
For instance
The area is:
