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4 years ago

4.5% of what number is 23?

Mathematics

1 answer:

TiliK225 [7]4 years ago

7 0

511.11111 is the answer the that problem

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What was the median number of posts made?

Svetradugi [14.3K]

Answer: The median number of posts made is 8.5

7 0

2 years ago

Do #11 I need help pleae

ryzh [129]

330 page/(3/4 Hour):==> 330 : 3/4
To solve this division you have to MULTIPLY the 1st term by the reciprocal of the 2nd (the reciprocal of 3/4 is 4/3), so

330 x 4/3 = (330x4)/3 = 440
330 pages were read in 3/4 Hour (given) & in 1 hour. could be read

3 0

3 years ago

Which of the following is equivalent to tan2θcos(2θ) for all values of θ for which tan2θcos(2θ) is defined?

Aloiza [94]

Answer:

2sin²θ - tan²θ

Step-by-step explanation:

Given

tan²θcos(2θ)

Required

Simplify

We start by simplifying cos(2θ)

cos(2θ) = cos(θ+θ)

From Cosine formula

cos(A+A) = cosAcosA - sinAsinA

cos(A+A) = cos²A - sin²A

By comparison

cos(2θ) = cos(θ+θ)

cos(2θ) = cos²θ - sin²θ ----- equation 1

Recall that cos²θ + sin²θ = 1

Make sin²θ the subject of formula

sin²θ = 1 - cos²θ

Substitute sin²θ = 1 - cos²θ in equation 1

cos(2θ) = cos²θ - (1 - cos²θ)

cos(2θ) = cos²θ - 1 +cos²θ

cos(2θ) = cos²θ + cos²θ - 1

cos(2θ) = 2cos²θ - 1

Substitute 2cos²θ - 1 for cos(2θ) in the given question

tan²θcos(2θ) becomes

tan²θ(2cos²θ - 1)

Open brackets

2cos²θtan²θ - tan²θ

------------------------

Simplify tan²θ

tan²θ = (tanθ)²

Recall that tanθ = sinθ/cosθ

So, we have

tan²θ = (sinθ/cosθ)²

tan²θ = sin²θ/cos²θ

------------------------

Substitute sin²θ/cos²θ for tan²θ

2cos²θtan²θ - tan²θ becomes

2cos²θ(sin²θ/cos²θ) - tan²θ

Open bracket (cos²θ will cancel out cos²θ) to give

2(sin²θ) - tan²θ

2sin²θ - tan²θ

Hence, the simplification of tan²θcos(2θ) is 2sin²θ - tan²θ

Option E is correct

7 0

3 years ago

Which table of values represents a function?

ser-zykov [4K]

I would say option 3 hopefully im right!!

7 0

3 years ago

Read 2 more answers

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

docker41 [41]

Given:

The table of values is

Number of Students : 7 14 21 28

Number of Textbooks : 35 70 105 140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

$\dfrac{35}{7}=5$

$\dfrac{70}{14}=5$

$\dfrac{105}{21}=5$

$\dfrac{140}{28}=5$

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

$\dfrac{y}{x}=k$

Here, k=5.

$\dfrac{y}{x}=5$

$y=5x$

Hence the rate of change is constant that is 5.

8 0

3 years ago