$D:x>0\\
\log x+\log x^2+\log x^3=-6\\
\log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\
x^6=10^{-6}\\
x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}$

8 0

3 years ago

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What is the equivalent factored form of 12x^4-42x^3-90x^2

Tanzania [10]

Factor the following:
12 x^4 - 42 x^3 - 90 x^2

Factor 6 x^2 out of 12 x^4 - 42 x^3 - 90 x^2:
6 x^2 (2 x^2 - 7 x - 15)

Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
6 x^2 x (2 x + 3) - 5 (2 x + 3)

Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
Answer: 6 x^2 (2 x + 3) (x - 5)

4 0

3 years ago

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line j is perpendicular to lines m and n. if the products of the slope of all three lines is -8, what is the slope of line j?

jeka94

Answer:

the slope of line j is -1/8, the slope of lines m and n are both 8.

Explanation step by step:

Suppose j is the slope of line j, m the slope of line m and n the slope of line n. Since:

1. line j is perpendicular of line m, so j*m= -1

2. J is perpendicular of line n, so j*n=-1

3. m and n and parallel so m=n