The volume of the Cl₂ gas is 4.15 L.
Explanation:
This problem can be easily solved using the ideal gas law.
As in ideal gas law, it is stated that the product of pressure and volume is equal to the product of number of moles with temperature with gas constant.
PV=nRT
So, in the present case, pressure P is given as 177 kPa, temperature T = 348 K and the mass of chlorine gas is given as 18 g.
So first step, we have to determine the value of 'n' using the mass of Chlorine gas given. The mass should be converted to moles by dividing the mass with molar mass of the gas.
As molar mass of Cl is 35.453 g/mol, then
So,
Then, the volume can be determined with R = 8.3144×10³ L Pa K⁻¹ mol⁻¹ as shown below:
Thus, the volume of the Cl₂ gas is 4.15 L.
The molar mass of is 86.02 g/mole
.
The molar mass of a chemical compound is represented as the mass of a unit of that compound separated by the number of substances in that unit, measured in moles. The molar mass is a volume, not molecular, the property of a substance.
The molar mass is a percentage of various examples of the compound, which usually change in mass due to the appearance of isotopes.
From the below attached table, the Molar mass of is 86.0108 g/mol.
This is an incomplete question, here is a complete question.
The balanced chemical reaction is:
In another experiment, if 80 molecules react with 104
molecules. How many
molecules will be produced which reactant will be used up in the reaction.
Answer : The number of molecules of will be, 52 molecules and
reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.
Explanation :
The balanced chemical reaction is:
First we have to determine the limiting reagent.
From the balanced reaction we conclude that,
As, 8 molecules of react with 6 molecule of
So, 104 molecules of react with
molecule of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the molecules of
From the reaction, we conclude that
As, 8 molecules of react to give 4 molecules of
So, 104 molecules of react to give
molecules of
Hence, the number of molecules of will be, 52 molecules and
reactant will be used up in the reaction because it is a limiting reagent and it limits the formation of product.