All categories

3 years ago

How is the wavelength of an electromagnetic wave related to the energy of the wave?

Chemistry

2 answers:

Sauron [17]3 years ago

6 0

The equation that relates both energy and wavelength is:

$e=\frac{h*c}{lambda}$

where e is the energy and lambda is the wavelength.

Therefore, as we can see from this equation, the energy of an electromagnetic wave is inversely related to the wavelength of the electromagnetic wave.

vivado [14]3 years ago

3 0

The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength.

You might be interested in

Given that 2S (s)+3O2 (g)→2SO3 (g)2SO2 (g)+O2 (g)→2SO3 (g) has an enthalpy change of −790.4 kJ has an enthalpy change of −198.2

abruzzese [7]

Answer:

The heat of formation of SO2 is -296.1 kJ

Explanation:

<u>Step 1:</u> Data given

2S (s)+3O2 (g)→2SO3 (g) ΔH = -790.4 kJ

2SO2 (g)+O2 (g)→2SO3 (g) ΔH = -198.2 kJ

<u>Step 2</u>: Calculate the heat of formation of SO2

2 S(s) + 3 O2(g) --> 2 SO3(g) ΔH = -790.4 kJ

S(s) + 3/2 O2(g) → SO3(g) ΔH = -395.2 kJ

2SO2 (g)+O2 (g)→2SO3 (g) ΔH = -198.2 kJ

SO3(g) → SO2(g) + 1/2 O2(g) ΔH = 99.1 kJ

----------------------------------------------------------------

S(s) + 3/2 O2(g) → SO3(g) ΔH = -395.2 kJ

SO3(g) → SO2(g) + 1/2 O2(g) ΔH = 99.1 kJ

-------------------------------------------------------------------

S (s)+O2 (g)→SO2 (g)

ΔHrxn = (-790.4 /2) kJ + (198.2/2) kJ

ΔHrxn = -395.2 kJ + 99.1 kJ = 296.1 kJ

The heat of formation of SO2 is -296.1 kJ

4 0

3 years ago

Age

cupoosta [38]

Answer:

Option (2)

Explanation:

Since the amount of each sample is the same, we are looking for the metal with the greatest density, which is copper.

5 0

1 year ago

Which is an example of flow of heat through conduction

JulsSmile [24]

Answer:

a metal spoon left in boiling water

Explanation:

5 0

2 years ago

Which type of intermolecular attractive force operates between (part A) all molecules, (part B) polar molecules, (part C) the hy

nydimaria [60]

Answer:

PART A: The LDF occurs between all molecules. Dispersion forces result from shifting electron clouds, which cause weak, temporary dipole.

PART B: Dipole dipole operates only between polar molecules. This is when two polar molecules get near each other and the positively charged portion of the molecule is attracted to the negatively charged portion of another molecule.

PART C: Dipole dipole and in some cases hydrogen bonding operate between the hydrogen atom of a polar bond and a nearby small electronegative atom. Only if the atom bonded to it were F, O or N it would be hydrogen bonding. Otherwise it is dipole dipole.

3 0

2 years ago

How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitro

abruzzese [7]

Answer:

Explanation:

oxygen is a 15 and nitrogen science chemistry i'm guessing

6 0

3 years ago