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kirza4 [7]
3 years ago
6

In a short paragraph, describe how I fuel cell works.

Chemistry
1 answer:
nirvana33 [79]3 years ago
7 0

Explanation:

passing hydrogen through the anode of a fuel cell and oxygen through the cathode.

hopes this helps

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How much of a sample remains after three half-lives have occurred? 1/16 of the original sample 1/9 of the original sample 1/8 of
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For this question, assume that you have 1 compound. This compound is divided in half once, so you are left with 0.5. That 0.5 that remains is divided in half again, this is the second half-life, and you are left with 0.25. The final half life involves dividing 0.25 in half, which means you are left with 0.125. For the answer to make sense, you need to know your conversions between decimals and fractions. To make it simple, if you have 0.125 and you times it by 8, you are left with your initial value of 1. Therefore, after three half-lives, you are left with 1/8th of the compound.
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a weight loss supplement i advertised in several popular beauty and and fashion magazines the advertisements claim that the supp
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to provide scientific evidence and results

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Carbon atoms can bond together in straight chains branched chains or rings. true or false
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Answer:

The answer to your question is: True

Explanation:

Carbon compounds

Aliphatic       saturated         only have single bonds

                     unsaturated    could have double or triple bonds

Ciclic            are skeletons of carbons that forms cycles

Aromatic      the unit of this compounds is benzene, which is a cycle of

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7 0
3 years ago
A sample substance has the chemical formula:
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Answer:

1,6,8

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Periodic Table- H=1.C=6,O=8

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A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume
ipn [44]

Answer : The final volume of gas will be, 103.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 740.0 mmHg  = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

P_2 = final pressure of gas = 99.3 kPa

V_1 = initial volume of gas = 106.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298K

T_2 = final temperature of gas = 20.0^oC=273+20.0=293K

Now put all the given values in the above equation, we get:

\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}

V_2=103.3L

Therefore, the final volume of gas will be, 103.3 L

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