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kirza4 [7]
3 years ago
6

In a short paragraph, describe how I fuel cell works.

Chemistry
1 answer:
nirvana33 [79]3 years ago
7 0

Explanation:

passing hydrogen through the anode of a fuel cell and oxygen through the cathode.

hopes this helps

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The bulb lights up in the circuit. Only two rods are conductors of electricity. Which one of the rods, X, Y or Z is definitely a
meriva

Answer: Rod X.

Explanation:

Ok, the electricity starts in the top left part. First, it must travel in the X rod, then it keeps traveling until it reaches the parallel path, and it can go to the Z rod, to the Y rod, or to both of them, and then it reaches the bulb (the circle with a X inside of it).

We know that two rods are conductors of electricity.

Now, suppose the case where rods Z and Y are the ones that conduct electricity, this means that X does not conduct electricity, then when the current reaches to X it stops (because X does not conduct) then the electricity never reaches the rods Z and Y, and then the electricity never reaches the bulb, but we know that the bulb lights up, so we must have that X is one of the conducting rods.

Then, if for example, Y does not conduct electricity, the electricity still can run through the Z rod and eventually reach the bulb.

So we can conclude that the rod that is definitely a conductor of electricity is rod X

4 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

<u>No of moles = mass of the substance÷molar mass of the substance</u>

No of moles of carbon = 14.4 /12= 1.2 moles

No of moles of O2 = Mass of reacted O2/Molar mass of O2.

No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

Mass of CO2 produced(x) = 1.2 x 44 = 52.8 g

<u>Thus 52.8 g of CO2 is produced.</u>

5 0
2 years ago
Identify the Lewis acid and Lewis base from among the reactants in each of the following equations. Match the words in the left
goldfiish [28.3K]

Answer:

1. Lewis acid: F. Fe₃⁺, Lewis base: B. CN⁻

2. Lewis acid: A. AlCl₃, Lewis base: D. Cl⁻

3. Lewis acid: C. AlBr₃, Lewis base: E. NH₃

Hope this helps.

8 0
2 years ago
Design a synthesis of acetophenone from benzene or toluene. 1275q Part 1 out of 5 Choose the best option for the nucleophile pre
Trava [24]

Answer:

A Fridiel craft catalyst will convert benzene to acetophenone.

Permanganate catalyst can be used to convert toluene to acetophenone.

Explanation:

Benzene can be reduced to acetophenone by the addition of anhydrous aluminium chloride, AlCl₃

The mechanism is as follows:

Benzene + Acetyl choloride → acetophenone

To convert toluene to acetophenone, the following steps are necessary:

  • Oxidation of Toluene to Benzoic acid.

     This is done by refluxing toluene with alkaline potassium permanganate         (KMnO₄+ Na₂CO₃).

  • Benzoic acid is converted to Benzoyl chloride by treating with thioyl chloride and heating at about 80 ⁰C.
  • Benzoyl chloride is treated with methyl lithium to form Acetophenone.
5 0
3 years ago
How to measure the volume of a substance in a test tube?
Naya [18.7K]
Hello!
Answer:
<span>Calculate Density Using Volume of a Cylinder.
That is one great way to measure the volume!
Hoping this helps you! ;D</span>
6 0
2 years ago
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