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Helen [10]
2 years ago
14

What is the total number of moles of hydrogen atoms contained in 1 mole of (nh42c2o4?

Chemistry
1 answer:
skad [1K]2 years ago
3 0
The answer is 8.  Hope this helps.
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Which planet is terrestrial?<br> Jupiter<br> Mars<br> O Saturn<br> Uranus
Zolol [24]

Answer: Mars

Explanation: The planet of Mars is the only planet of all that is terrestrial. Jupiter, Saturn and Neptune are all Jovian Planets. The answer to the question is Mars. Hope this answer helps you!

4 0
2 years ago
Read 2 more answers
`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma
Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

2Al + 6HCl\rightarrow 2AlCl_3 +3H_2

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when \frac{2}{3} moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when \frac{2}{3}\times 10.0 moles of aluminium undergoes reaction.

<u>Moles of Al needed  = \frac{2}{3}\times 10.0 moles = 6.67 moles</u>

6 0
3 years ago
Can someone please help me on the second one? I have no idea what to do.
Aleks [24]

The reaction will produce 12.1 g Ag₂S.

<em>Balanced equation</em> = 2Ag + S ⟶ Ag₂S

<em>Mass of Ag₂S</em> = 10.5 g Ag × (1 mol Ag/107.87 g Ag) × (1 mol Ag₂S/2 mol Ag)

× (247.80 g Ag₂S/1 mol Ag₂S) = 12.1 g Ag₂S

8 0
3 years ago
If you pump air into cycle tyre a slight warming effect is noticed at valve stem why
SSSSS [86.1K]
Probably the kinetic energy of rubbing the pump against the valve, combined with the increase in gas pressure in the tire itself.
8 0
3 years ago
Determine the volume of water to be added to the nitric acid solution at a concentration of 8.61 mol / L to prepare 500 mL of th
Alex_Xolod [135]

Answer:

398 mL

Explanation:

Using the equation for molarity,

C₁V₁ = C₂V₂ where C₁ = concentration before adding water = 8.61 mol/L and V₁ = volume before adding water, C₂ = concentration after adding water = 1.75 mol/L and V₂ = volume after adding water = 500 mL = 0.5 L

V₂ = V₁ + V' where V' = volume of water added.

So, From C₁V₁ = C₂V₂

V₁ =  C₂V₂/C₁

= 1.75 mol/L × 0.5 L ÷ 8.61 mol/L

= 0.875 mol/8.61 mol/L

= 0.102 L

So, V₂ = V₁ + V'

0.5 L = 0.102 L + V'

V' = 0.5 L - 0.102 L

= 0.398 L

= 398 mL

So, we need to add 398 mL of water to the nitric solution.

6 0
2 years ago
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