Answer:
C₃H₄O₃
Explanation:
The empirical formula is the simplest whole-number ratio of atoms present in a molecule. To solve this question we must find the moles of CO2 = Moles of Carbon and moles of H2O = 1/2 moles H.
With the difference in masses of the atoms we can find the mass of ascorbic acid and its moles as follows:
<em>Moles CO2 = Moles C -Molar mass: 44.01g/mol-</em>
4.31g CO2 * (1mol / 44.01g) = 0.0979 moles C * (12.01g/mol) = 1.18g C
<em>Moles H2O -Molar mass: 18.01g/mol</em>
1.17g H2O * (1mol / 18.01g) = 0.0650 moles H2O * (2mol H / 1mol H2O) = 0.130 moles H = 0.13g H
<em>Moles O:</em>
Mass O: 2.87g-0.13g H - 1.18g C = 1.56g O
<em>Moles O:</em>
1.56g O * (1mol/16g) = 0.0975 moles O
Dividing each number of moles of atoms in the moles of Oxygen (The lower number of moles:
O/O = 0.0975 moles O/0.0975 moles O = 1
H/O = 0.130 moles H/ 0.0975 moles O = 1.333
C/O = 0.0979 moles C/ 0.0975 moles O = 1
As empirical formula requires whole-numbers we need to multiply this ratio 3 times:
O = 1*3 = 3
H = 1.333*3 = 4
C = 1*3 = 3
Empirical formula of ascorbic acid is:
<h3>C₃H₄O₃</h3>
Answer:
-1.78 V
Explanation:
There are several rules required to calculate the cell potential:
- given standard cell potential, we may reverse the equation: the products of a given reaction become our reactants, while reactants become our products in the reversed equation. For a reversed equation, we change the sign of the cell potential to the opposite sign;
- if we multiply the whole equation by some number, this doesn't influence the cell potential value. It only produces a different expression in the equilibrium constant.
That said, notice that the initial reaction with respect to the final reaction is:
- reversed: chromium(III) cation and chloride anion become our reactants as opposed to the products in the initial reaction, so we change the sign of the cell potential to a negative value of -1.78 V;
- each coefficient is multiplied by a fraction of . It doesn't influence the value of the cell potential.
Thus, we have a cell of E = -1.78 V.
Answer:
Apex answer is: A. the solute becomes less ordered
Explanation:
<h3>Answer:</h3>
1.5 × 10⁸ Kg of CO₂ / Year
<h3>Solution:</h3>
According to statement,
1 kwh generation produces = 0.73 Kg of CO₂
So,
700 kwh generation will produce = X Kg of CO₂
Solving for X,
X = (700 kwh × 0.73 Kg) ÷ 1 kwh
X = 511 Kg of CO₂ / Year
Also, as calculated,
1 household produces = 511 Kg of CO₂ / Year
Then,
300,000 households will produce = X Kg of CO₂ per Year
Solving for X,
X = (300000 households × 511 Kg) ÷ 1 household
X = 153300000 Kg of CO₂ / Year
Or,
X = 1.5 × 10⁸ Kg of CO₂ / Year