V₁ = 900.0 mL
T₁ = 27.0ºC + 273 = 300 K
V₂ = ?
T₂ = 132.0 + 273 = 405 K
V₁ / T₁ = V₂ / T₂
900.0 / 300 = V₂ / 405
300 x V₂ = 405 x 900.0
300 x V₂ = 364500
V₂ = 364500 / 300
V₂ = 1215 mL
hope this helps!
The substance with pH are basic, so correct answer is <span>C) more OH- ions than H30+ ions.</span>
No! If it was 12% a 150 pound person would be about 18 pounds of salt!
~0.4%
The average 150lb person would contain ~280 g of NaCl.
Answer:
the answer is b,the answer has to be even though I'm not very sure about it
The number of moles of NO₂ that would be produced from 3.9 mol of O₂ in the reaction is 5.13 moles NO2.
<h3>What is nitrogen?</h3>
Nitrogen is a monatomic gas. It is the most abundant gas present in the environment.
4.5 mol O2 x (2 mol NO2/ 1 mol O2) = 9 mol NO2
For 57% yield of the reaction
9 mol NO2 x 0.57 = 5.13 moles NO2.
Thus, the number of moles of NO₂ is 5.13 moles.
Learn more about nitrogen
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