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LenaWriter [7]
3 years ago
15

Name the type of equation shown here: 2NaBr+Ca(OH)2 —>CaBr2+2NaOH

Chemistry
2 answers:
sergeinik [125]3 years ago
6 0
A) Double replacement
Because the reactants switch when they become products
erma4kov [3.2K]3 years ago
6 0

Answer: A) double replacement

Explanation:

1. Double displacement reaction is one in which exchange of ions take place.  

Example: 2NaBr+Ca(OH)_2\rightarrow CaBr_2+2NaOH

2. Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

Example: Zn+2HCl\rightarrow ZnCl_2+H_2

3. Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.

Example:  

C_6H_{12}O_6+O_2 \rightarrow CO_2+H_2O

4. Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

Example: Li_2O+CO_2\rightarrow Li_2CO_3  

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3 years ago
Water can be formed in the following reaction:
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The  moles  of  oxygen  gas (O2) that is needed is    4  moles


 Explanation

2H2 +O2 → 2H2O

The  moles of O2  is determined using the mole  ratio  of H2:O2

that is from equation  above H2:O2  is 2:1  

If the moles of H2  is 8  moles therefore  the moles  of O2

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3 years ago
A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to
melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:

  • pH = pKa + log\frac{[CH_3COO^-]}{[CH_3COOH]}

For acetic acid, pKa = 4.75.

We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:

  • CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
  • CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:

  • pH = 4.75 + log\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L} = 5.54
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Your answer would be they have mobile ions in solution.
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