Name the type of equation shown here: 2NaBr+Ca(OH)2 —>CaBr2+2NaOH

Chemistry

2 answers:

sergeinik [125]3 years ago

6 0

A) Double replacement
Because the reactants switch when they become products

erma4kov [3.2K]3 years ago

6 0

Answer: A) double replacement

Explanation:

1. Double displacement reaction is one in which exchange of ions take place.

Example: $2NaBr+Ca(OH)_2\rightarrow CaBr_2+2NaOH$

2. Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.

Example: $Zn+2HCl\rightarrow ZnCl_2+H_2$

3. Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.

Example:

$C_6H_{12}O_6+O_2 \rightarrow CO_2+H_2O$

4. Synthesis reaction is a chemical reaction in which two reactants are combining to form one product.

Example: $Li_2O+CO_2\rightarrow Li_2CO_3$

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8 0

3 years ago

8.0 mol AgNO3 reacts with 5.0 mol Zn in

Yakvenalex [24]

Taking into account the reaction stoichiometry, 8 moles of Ag can be produced from 8 moles of AgNO₃ and 5 moles of Zn.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 AgNO₃ + Zn → 2 Ag + Zn(NO₃)₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

AgNO₃: 2 moles
Zn: 1 mole
Ag: 2 moles
Zn(NO₃)₂: 1 mole

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 1 mole of Zn reacts with 2 moles of AgNO₃, 5 moles of Zn reacts with how many moles of AgNO₃?

$amount of moles of AgNO_{3}= \frac{5 moles of Znx2 moles of AgNO_{3}}{1 mole of Zn}$

<u><em>amount of moles of AgNO₃= 10 moles </em></u>

But 10 moles of AgNO₃ are not available, 8 moles are available. Since you have less moles than you need to react with 5 moles of Zn, AgNO₃ will be the limiting reagent.

<h3>Moles of Ag formed</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 2 moles of AgNO₃ form 2 moles of Ag, 8 moles of AgNO₃ form how many moles of Ag?

$amount of moles of Ag=\frac{8 moles of AgNO_{3}x2 moles of Ag }{2 moles of AgNO_{3}}$