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Sati [7]
3 years ago
11

Which criteria determine whether a heterogeneous mixture is a colloid or a suspension?

Chemistry
2 answers:
lianna [129]3 years ago
6 0
The correct answer is B. whether the particles do not settle for an extended period of time

Uniformity and transparency are not affected by these, which also applies to ratio fixedness.
vivado [14]3 years ago
5 0
Correct Answer: Option B: <span>whether the particles do not settle for an extended period of time

Reason:
Particle size in colloidal solution ranges from 1-100 nm, while that is suspension is more than 100 nm. Due to large particle size, particles in suspension settle down, upon standing for long. Thus, the best </span>criteria determine whether a heterogeneous mixture is a colloid or a suspension is to check <span>whether the particles do not settle for an extended period of time</span>
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What element from the "Periodic Table" is named after an "Austrian Scientist"??
soldier1979 [14.2K]

Answer:

Should be either mendele or fermium

maybe lawrencium not sure but I think it’s lawrencium! Sorry if wrong heh

Explanation: <u><em>really trying to help! If it’s wrong super sorry!!!</em></u>

3 0
3 years ago
Explain, in terms of subatomic particles, why the radius of a chloride ion is larger than the radius of a chlorine atom.
den301095 [7]
The radius of a chlorine ion is larger than the radius of a chlorine atom because  the effective nuclear charge decreases, therefore the inward force decreases, increasing the ionic radius.
6 0
3 years ago
How many miles are in 1.50^22 atoms of silver?
Whitepunk [10]
Should be 33. but I habe no clue
4 0
3 years ago
Read 2 more answers
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8 0
3 years ago
If 42 grams of carbon and 52 grams of oxygen are used, how many grams of CO2 will be produced (Hint: find the
zavuch27 [327]

Answer:

71.5g

Explanation:

The reaction equation is given as:

               C  +  O₂  →  CO₂

Mass of C = 42g

Mass of O₂  = 52g

Unknown:

Mass of CO₂ produced  = ?

Solution

Now to solve this problem, we have to find limiting reactant which is the one given in short supply in this reaction.

 The extent of the reaction is controlled by this reactant.

Find the number of moles of the given species;

 Number of moles  = \frac{mass}{molar mass}

      Number of moles of C  = \frac{42}{12}   = 3.5mol

     Number of moles of O₂   = \frac{52}{32}   = 1.63mol

Now;

   From the balanced reaction equation;

           1 mole of C reacted with 1 mole of O₂

We see that C is in excess and O₂ is the limiting reactant.

            1 mole of O₂ will produce 1 mole of CO₂

 So;      1.63mole of O₂ will produce 1.63 mole of CO₂

Mass of CO₂ = number of moles x molar mass

       Molar mass of CO₂ = 44g/mol

Mass of CO₂ = 1.63 x 44 = 71.5g

8 0
3 years ago
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