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aniked [119]
3 years ago
13

Describe how you could prove that a bicycle is matter

Chemistry
1 answer:
Ainat [17]3 years ago
5 0

Answer:

Explanation:

Matter is anything that has weight and occupies space.

To prove that a bicycle is a matter, we need to show that it has weight and will occupy space.

When you put the bicycle on a weighing scale, you will see the weight of the bicycle. This a proof that bicycle is a matter.

To show that the bicycle can occupy space, place the device in a tank full of water. From the tank, the bicycle will displace some water. Substances that cannot occupy space will not behave in such manner.

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Second choice is correct
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Why pie bond are not perticipate in hybridaization​
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The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.
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At room temperature and pressure, 0.4 g of neon will occupy what volume<br> of gas?
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Answer:

"One mole of any gas has a volume of 24 dm3 or 24,000 cm3 at rtp (room temperature and pressure). This volume is called the molar volume of a gas."

Explanation:

Divide the mass of neon.

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An alcohol that contains only one -oh group can be classified as a
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Alkanol [having only one oh group]
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Ammonium nitrate, a common fertilizer, is used as an explosive in fireworks and by terrorists. It was the material used in the t
Sladkaya [172]

Explanation:

The given balanced reaction is as follows.

           2NH_{4}NO_{3} \rightarrow 2N_{2} + O_{2} + 4H_{2}O

It is given that mass of ammonium nitrate is 86.0 kg.

As 1 kg = 1000 g. So, 86.0 kg = 86000 g.

Hence, moles of NH_{4}NO_{3} present will be as follows.

      Moles of NH_{4}NO_{3} = \frac{mass given}{\text{molar mass of NH_{4}NO_{3}}}

                                  = \frac{86000 g}{80.043 g/mol}

                                  = 1074.42 mol

Therefore, moles of N_{2}, O_{2} and H_{2}O produced by 1074.42 mole of NH_{4}NO_{3} will be as follows.

  Moles of O_{2} = \frac{1}{2} \times 1074.42 mol

                                = 537.21 mol

Moles of N_{2} = \frac{2}{2} \times 1074.42 mol

                                = 1074.42 mol

Moles of H_{2}O = \frac{4}{2} \times 1074.42 mol

                                = 2148.84 mol

Therefore, total number of moles will be as follows.

          537.21 mol + 1074.42 mol + 2148.84 mol

        = 3760.47 mol

According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.

                       PV = nRT

                     1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex]         (as 307^{o}C = 307 + 273 = 580 K)

                           V = 179066.06 L

Thus, we can conclude that total volume of the gas is 179066.06 L.

3 0
3 years ago
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