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kupik [55]
3 years ago
12

Which of the following solvents would be the best to separate a mixture containing benzoic acid, 2,4-dinitrobenzoic acid, and 2,

4,6-trinitrobenzoic acid by TLC?
A. Methylene chloride
B. Hexane
C. Acetone
D. None of the above
Chemistry
1 answer:
KatRina [158]3 years ago
4 0

Answer:

The correct option is Methylene chloride

Explanation:

Methylene chloride or Dichloromethane has an organic formula of CH2CL2. it is commonly used as solvent, it is very volatile and dissolves many organic compounds including a mixture containing benzoic acid, 2,4-dinitrobenzoic acid, and 2,4,6-trinitrobenzoic acid. It is colorless, has a chloroform like odor and Miscible in ethyl acetate, alcohol, hexanes, benzene, CCl4, diethyl ether, CHCl3.

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What is the [OH-]if the pH of a solution 10.62
Lerok [7]
As we know,

                     pH + pOH  =  14
Or,
                     pOH  =  14 - pH

Putting Value of pH,

                    pOH  =  14 - 10.62

                    pOH  =  3.38

pOH is converted into [OH⁻] as follow,

                   [OH⁻]  =  10⁻pOH             ∴ -pOH is in power, 10 means antilog
                                                               press shift and click log button
                   [OH⁻]  =  10⁻³°³⁸

                   [OH⁻]  =  0.0004168

                   [OH⁻]  =  4.16 × 10⁻⁴
5 0
3 years ago
Hi All,
Novosadov [1.4K]

Answer:Combination.

Decomposition.

Single displacement.

Double displacement.

Combustion.

Redox.

Explanation:

4 0
3 years ago
Which of the following pairs of compounds would you expect to form homogeneous solutions when combined? a)CH3CH2CH2CH2CH3 AND CH
Stolb23 [73]
<span>Which of the following pairs of compounds would you expect to form homogeneous solutions when combined?
</span><span>a) CH3CH2CH2CH2CH3 AND CH3CH2CH2CH2CH2CH3
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8 0
3 years ago
A weak monoprotic acid is titrated with 0.100 MNaOH. It requires 50.0 mL of the NaOH solution to reach the equivalence point. Af
larisa86 [58]

Explanation:

The given reaction is as follows.

        HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Hence, number of moles of NaOH are as follows.

        n = 0.05 L \times 0.1 M

           = 0.005 mol

After the addition of 25 ml of base, the pH of a solution is 3.62. Hence, moles of NaOH is 25 ml base are as follows.

             n = 0.025 L \times 0.1 M

                = 0.0025 mol

According to ICE table,

         HA(aq) + NaOH (aq) \rightleftharpoons NaA(aq) + H_{2}O(l)

Initial:     0.005 mol   0.0025 mol              0                  0

Change: -0.0025 mol  -0.0025 mol        +0.0025 mol

Equibm:   0.0025 mol    0                         0.0025 mol

Hence, concentrations of HA and NaA are calculated as follows.

          [HA] = \frac{0.0025 mol}{V}

        [NaA] = \frac{0.0025 mol}{V}

       [A^{-}] = [NaA] = \frac{0.0025 mol}{V}

Now, we will calculate the pK_{a} value as follows.

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       pK_{a} = pH - log \frac{[A^{-}]}{[HA]}

                  = 3.42 - log \frac{\frac{0.0025 mol}{V}}{\frac{0.0025}{V}}

                  = 3.42

Thus, we can conclude that pK_{a} of the weak acid is 3.42.

           

8 0
3 years ago
WILL MARK BRAINIEST <br><br> Can someone please help me understand this?
Mila [183]

To convert from moles to grams you divide by the molar mass of the element. To convert from grams to moles you X by the molar mass element

5 0
3 years ago
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